如何使用解析 iOS 进行"Most Popular"

Question

在我的项目中，用户提交了一个故事，我试图把它放在"流行页面"上最受关注的位置，但没有找到方法。这是我到目前为止的代码，提前感谢，是的，我知道它不多，但有什么帮助。

MasterViewContoller.m

-(id)initWithCoder:(NSCoder *)aDecoder {
    self = [super initWithCoder:aDecoder];
    if (self) {
        // Customize the table
        // The className to query on
        self.className = @"Word";
        // The key of the PFObject to display in the label of the default cell style
        self.textKey = @"by";
        // Uncomment the following line to specify the key of a PFFile on the PFObject to display in the imageView of the default cell style
        // self.imageKey = @"image";
        // Whether the built-in pull-to-refresh is enabled
        self.pullToRefreshEnabled = YES;
        // Whether the built-in pagination is enabled
        self.paginationEnabled = YES;
        // The number of objects to show per page
        self.objectsPerPage = 25;
    }
    return self;
}

云代码

Parse.Cloud.beforeSave("Word", function(request, response) {
var wordText = request.Object.get("wordText");
var attribution = request.Object.get("by");
if(wordText.length){
    if (attribution.length){
            response.success();
            }else{
            request.object.set("by", "annoymous");
            response.success();
    }
    }else{
    response.error("Not valid. Please fill in all text");
}
});

Answer 1

您可以尝试在"Word"对象中创建另一个int类型的键（例如，我们称之为timesViewed），这样，每当不是currentUser的PFUser查看该对象时，timesViewed就会增加一。然后用[query orderByDescending:@"timesViewed]查询timesViewed。