'int'对象不可调用

Question

我正在制作一个简单的python脚本来处理一个表。我正在使用数组来存储单元格值。这是代码：

table =[]
hlen = input("Please enter the amount of columns n")
vlen = input("Please enter the amount of rows n")
curcol = 1
currow = 1
totcell = hlen*vlen
while (totcell >= curcol * currow):
   str = input("Please input "+ str(curcol) +"," + str(currow))
   table.append(str)
   if (curcol >= hlen):
       currow =+ 1
//Process Table

该程序运行甜蜜，要求第一个单元格为 1,1。一切都很好，直到代码在重新加载时停止。这是蟒蛇错误输出

Traceback (most recent call last):
  File "./Evacuation.py", line 13, in <module>
    str = input("Please input "+ str(curcol) +"," + str(currow))
TypeError: 'int' object is not callable

感谢您的任何帮助。

Answer 1

你正在使用你的变量名来隐藏内置str：

str = input("Please input "+ str(curcol) +"," + str(currow))

第二次，你试图用str(currow)打电话给str，现在是一个int

说出它的名字！

此外，您使用的是Python 2，因此最好使用raw_input而不是input

Answer 2

  m = input("Please input "+ str(curcol) +"," + str(currow))
  please use different name of variable not use 'str' because it is python default function for type  casting
  table =[]
  hlen = input("Please enter the amount of columns n")
  vlen = input("Please enter the amount of rows n")
  curcol = 1
  currow = 1
  totcell = hlen*vlen
  while (totcell >= curcol * currow):
       m = input("Please input "+ str(curcol) +"," + str(currow))
  table.append(m)
  if (curcol >= hlen):
    currow += 1

   Please enter the amount of columns 
   5
  Please enter the amount of rows 
   1
  Please input 1,11
  Please input 1,11
  Please input 1,1
  >>> ================================ RESTART ================================
  >>> 
  >>>Please enter the amount of columns 
  >>>1
  Please enter the amount of rows 
  1
 Please input 1,12

 see this program and run it .

Answer 3

您使用str作为从输入返回int的变量名称。当你使用 str（curcol） 和 str（currow） 时，Python 指的是它，而不是 Python 字符串函数。