XSL分组和子分组

Question

我在Muenchian上找到了这篇文章，将XSLT 1.0组分组，并与我想做的事情一部分，但是我无法弄清楚如何分组我的子节点。<<<<<<<<<<<<<<<<<</p>

我的XML看起来有点像这样：

<NewDataSet>
   <Vehicle>
     <ManufacturerId>53</ManufacturerId>
     <ManufacturerName>VAUXHALL</ManufacturerName>
     <Model>Corsa</Model>
   </vehicle>
   <Vehicle>
     <ManufacturerId>53</ManufacturerId>
     <ManufacturerName>VAUXHALL</ManufacturerName>
     <Model>Astra</Model>
   </vehicle>
   <Vehicle>
     <ManufacturerId>53</ManufacturerId>
     <ManufacturerName>VAUXHALL</ManufacturerName>
     <Model>Corsa</Model>
   </vehicle>
   <Vehicle>
     <ManufacturerId>54</ManufacturerId>
     <ManufacturerName>FORD</ManufacturerName>
     <Model>KA</Model>
   </vehicle>
   <Vehicle>
     <ManufacturerId>54</ManufacturerId>
     <ManufacturerName>FORD</ManufacturerName>
     <Model>Focus</Model>
   </vehicle>
   <Vehicle>
     <ManufacturerId>54</ManufacturerId>
     <ManufacturerName>FORD</ManufacturerName>
     <Model>KA</Model>
   </vehicle>
   <Vehicle>
     <ManufacturerId>55</ManufacturerId>
     <ManufacturerName>CITROEN</ManufacturerName>
     <Model>C4</Model>
   </vehicle>
<NewDataSet>

这是我到目前为止的代码

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:output method="html" omit-xml-declaration="yes" />
   <xsl:key name="groups" match="/NewDataSet/Vehicle" use="ManufacturerName" />
   <xsl:template match="/NewDataSet">
      <xsl:apply-templates select="Vehicle[generate-id() = generate-id(key('groups', ManufacturerName)[1])]"/>
   </xsl:template>
   <xsl:template match="Vehicle">
     <div class="makeLnk">
     <a href="/stocklist/?ManufacturerId={ManufacturerId}"><xsl:value-of select="ManufacturerName"/></a>
    <xsl:for-each select="key('groups', ManufacturerName)">
      <div class="modelLnk"><xsl:value-of select="Model"/></div>
    </xsl:for-each>
    </div>
   </xsl:template>
</xsl:stylesheet>

这将制造商组合在一起，并列出了下面的所有模型。但是我现在也想对模型进行分组，从而删除重复的名称。但是无法弄清楚语法。

感谢任何帮助。

谢谢。

Answer 1

使用由Vehicle的ManufacturerName组成的第二个键和Model的值：

<xsl:key name="model" match="Vehicle/Model" use="concat(../ManufacturerName, '|', .)"/>

然后更换

   <xsl:template match="Vehicle">
     <div class="makeLnk">
     <a href="/stocklist/?ManufacturerId={ManufacturerId}"><xsl:value-of select="ManufacturerName"/></a>
    <xsl:for-each select="key('groups', ManufacturerName)">
      <div class="modelLnk"><xsl:value-of select="Model"/></div>
    </xsl:for-each>
    </div>
   </xsl:template>

   <xsl:template match="Vehicle">
     <div class="makeLnk">
     <a href="/stocklist/?ManufacturerId={ManufacturerId}"><xsl:value-of select="ManufacturerName"/></a>
    <xsl:for-each select="key('groups', ManufacturerName)/Model[generate-id() = 
  generate-id(key('model', concat(../ManufacturerName, '|', .))[1])]">
      <div class="modelLnk"><xsl:value-of select="."/></div>
    </xsl:for-each>
    </div>
   </xsl:template>