以下是我的代码,即使键存在:
import java.util.HashMap;
import java.util.Map;
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
public class SequenceNumber {
public static int getSequenceNumber (String TcOrderId){
// Create a hash map to set key values pair.
Map<String, Integer> map = new HashMap<String, Integer>();
int i= 1;
// check if hashmap contains the key.
System.out.println("key present " +map.containsKey(TcOrderId));
if (map.containsKey(TcOrderId))
{
//Key Present
System.out.println("Inside IF ");
int value = map.get(TcOrderId);
System.out.println("value from the key " + value);
map.remove(value);
map.put(TcOrderId, value+1);
return map.get(TcOrderId);
}
else
{
//Key Not present
System.out.println("INSIDE ELSE ");
map.put(TcOrderId, i);
System.out.println("map "+ map);
return map.get(TcOrderId);
}
}
public static void main(String[] args) throws IOException {
String sCurrentLine;
BufferedReader br = null;
try {
br = new BufferedReader(new FileReader("C:\Users\BongAn\Desktop\Package\testing.txt"));
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
{
while ((sCurrentLine = br.readLine()) != null) {
//String orderid = sCurrentLine.substring(0, 6);
System.out.println("reading line " +sCurrentLine);
int seqvalue = getSequenceNumber(sCurrentLine);
System.out.println("seqvalue "+seqvalue);
}
}
}
}
文件中的输入数据:
1233
1233
1234
结果应该是
1
2
1
,但每次它都进入其他循环,结果为
1
1
1
我正在创建自己的索引时尝试使用hashmap。
在您的代码中,每次调用get sequencenumber函数 - 您创建新的哈希图。我相信这不是您想要的。
避免这种情况 - 您可以简单地将Map<String, Integer> map = new HashMap<String, Integer>();
移至课堂上。由于函数get -sequencenumber是一个静态函数 - 您需要使变量静态。希望这会有所帮助。
代码:
public class SequenceNumber {
// PUT STATIC VARIABLE HERE:
static Map<String, Integer> map = new HashMap<String, Integer>();
public static int getSequenceNumber (String TcOrderId){
// Create a hash map to set key values pair.
// (REMOVE) Map<String, Integer> map = new HashMap<String, Integer>();**
int i= 1;
// check if hashmap contains the key.
...
}
...
}
另一种替代
(也许更好)是避免静态功能和变量,并创建一个序列对象的实例。这样,您可以单独保留几个不同的实例编号。
简单片段:
public class SequenceNumber {
// Your hashmap here:
Map<String, Integer> map = new HashMap<String, Integer>();
public int getSequenceNumber (String TcOrderId) {
// ...
}
public static void main(String[] args) throws IOException {
// Instance of SequenceNumber object:
SequenceNumber sequenceNumber = new SequenceNumber();
String sCurrentLine;
BufferedReader br = null;
// ...
while ((sCurrentLine = br.readLine()) != null) {
//String orderid = sCurrentLine.substring(0, 6);
System.out.println("reading line " +sCurrentLine);
int seqvalue = sequenceNumber.getSequenceNumber(sCurrentLine);
System.out.println("seqvalue "+seqvalue);
}
// ...
}
}
类似的东西应该起作用。
还没有尝试过。public class SequenceNumber {
public static int getSequenceNumber (String TcOrderId, Map<String, Integer> map){
if(!map.contains(TcOrderId)){
map.put(TcOrderId, 0);
}
map.put(TcOrderId, map.get(TcOrderId)+1);
return map.get(TcOrderId);
}
public static void main(String[] args) throws IOException {
String sCurrentLine;
BufferedReader br = null;
Map<String, Integer> map = new HashMap<String, Integer>();
try {
br = new BufferedReader(new FileReader("C:\Users\BongAn\Desktop\Package\testing.txt"));
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
{
while ((sCurrentLine = br.readLine()) != null) {
//String orderid = sCurrentLine.substring(0, 6);
System.out.println("reading line " +sCurrentLine);
int seqvalue = getSequenceNumber(sCurrentLine, map);
System.out.println("seqvalue "+seqvalue);
}
}