我遇到了一个我一直无法解决的奇怪错误。我正在为考试而学习,所以我用structs而不是class,因为我们在课堂上就是这么做的。这是我的代码
#include <iostream>
#include <string>
using namespace std;
struct Course;
ostream &operator<<(ostream &os, Course c);
struct Course {
string name;
Course(string n) {
name = n;
}
Course(const Course &c) {
cout << "Copying course" << endl;
name = c.name;
}
Course &operator=(const Course &c) {
cout << "Assigning course" << endl;
name = c.name;
return *this;
}
};
struct Student {
int id;
Course *courses[5];
int size;
Student(int num) {
id = num;
for (int i = 0; i < 5; i++) {
courses[i] = new Course("Course");
}
size = 0;
}
Student(const Student &s) {
cout << "Copying student" << endl;
id = s.id;
for (int i = 0; i < 5; i++) {
Course *temp = new Course(s.courses[i]->name);
courses[i] = temp;
}
}
Student &operator=(const Student &s) {
cout << "Assigning student" << endl;
id = s.id;
for (int i = 0; i < 5; i++) {
courses[i] = s.courses[i];
}
return *this;
}
~Student() {
for (int i = 0; i < 5; i++) {
delete courses[i];
}
}
void print() {
cout << id << ": " << endl;
for (int i = 0; i < 5; i++) {
cout << courses[i]->name << endl;
}
}
void addCourse(Course *c) {
delete courses[size];
courses[size] = c;
size++;
}
};
ostream &operator<<(ostream &os, Course *c) {
return os << c->name << endl;
}
int main() {
Student one(2342134);
Course cs246("cs246");
Course cs245("cs245");
one.addCourse(&cs246);
one.addCourse(&cs245);
one.print();
Student two = one;
two.print();
}
这是错误
2342134:
cs246
cs245
Course
Course
Course
Copying student
2342134:
cs246
cs245
Course
Course
Course
*** glibc detected *** ./a.out: double free or corruption (fasttop): 0x0000000000cd8db0 ***
======= Backtrace: =========
/lib/x86_64-linux-gnu/libc.so.6(+0x7db26)[0x7f359a7ddb26]
/usr/lib/x86_64-linux-gnu/libstdc++.so.6(_ZNSsD1Ev+0x40)[0x7f359adf87c0]
./a.out[0x40111e]
./a.out[0x401152]
./a.out[0x400dc7]
/lib/x86_64-linux-gnu/libc.so.6(__libc_start_main+0xed)[0x7f359a78176d]
./a.out[0x400b89]
======= Memory map: ========
00400000-00402000 r-xp 00000000 00:34 45960378 /u3/z38ahmed/cs246/1161/exam/2.22_Object/2.22.5_Copy-Constructor-and-Assignment/a.out
00601000-00602000 r--p 00001000 00:34 45960378 /u3/z38ahmed/cs246/1161/exam/2.22_Object/2.22.5_Copy-Constructor-and-Assignment/a.out
00602000-00603000 rw-p 00002000 00:34 45960378 /u3/z38ahmed/cs246/1161/exam/2.22_Object/2.22.5_Copy-Constructor-and-Assignment/a.out
00cc7000-00cf9000 rw-p 00000000 00:00 0 [heap]
7f359a460000-7f359a55b000 r-xp 00000000 fc:00 915519 /lib/x86_64-linux-gnu/libm-2.15.so
7f359a55b000-7f359a75a000 ---p 000fb000 fc:00 915519 /lib/x86_64-linux-gnu/libm-2.15.so
7f359a75a000-7f359a75b000 r--p 000fa000 fc:00 915519 /lib/x86_64-linux-gnu/libm-2.15.so
7f359a75b000-7f359a75c000 rw-p 000fb000 fc:00 915519 /lib/x86_64-linux-gnu/libm-2.15.so
7f359a760000-7f359a914000 r-xp 00000000 fc:00 915563 /lib/x86_64-linux-gnu/libc-2.15.so
7f359a914000-7f359ab13000 ---p 001b4000 fc:00 915563 /lib/x86_64-linux-gnu/libc-2.15.so
7f359ab13000-7f359ab17000 r--p 001b3000 fc:00 915563 /lib/x86_64-linux-gnu/libc-2.15.so
7f359ab17000-7f359ab19000 rw-p 001b7000 fc:00 915563 /lib/x86_64-linux-gnu/libc-2.15.so
7f359ab19000-7f359ab1e000 rw-p 00000000 00:00 0
7f359ab20000-7f359ab36000 r-xp 00000000 fc:00 914560 /lib/x86_64-linux-gnu/libgcc_s.so.1
7f359ab36000-7f359ad35000 ---p 00016000 fc:00 914560 /lib/x86_64-linux-gnu/libgcc_s.so.1
7f359ad35000-7f359ad36000 r--p 00015000 fc:00 914560 /lib/x86_64-linux-gnu/libgcc_s.so.1
7f359ad36000-7f359ad37000 rw-p 00016000 fc:00 914560 /lib/x86_64-linux-gnu/libgcc_s.so.1
7f359ad38000-7f359ae3a000 r-xp 00000000 fc:00 396701 /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.21
7f359ae3a000-7f359b039000 ---p 00102000 fc:00 396701 /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.21
7f359b039000-7f359b041000 r--p 00101000 fc:00 396701 /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.21
7f359b041000-7f359b043000 rw-p 00109000 fc:00 396701 /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.21
7f359b043000-7f359b046000 rw-p 00000000 00:00 0
7f359b048000-7f359b06a000 r-xp 00000000 fc:00 915535 /lib/x86_64-linux-gnu/ld-2.15.so
7f359b268000-7f359b26a000 rw-p 00000000 00:00 0
7f359b26a000-7f359b26b000 r--p 00022000 fc:00 915535 /lib/x86_64-linux-gnu/ld-2.15.so
7f359b26b000-7f359b26d000 rw-p 00023000 fc:00 915535 /lib/x86_64-linux-gnu/ld-2.15.so
7f359b26d000-7f359b274000 rw-p 00000000 00:00 0
7ffdfdac4000-7ffdfdae5000 rw-p 00000000 00:00 0 [stack]
7ffdfdb78000-7ffdfdb7a000 r-xp 00000000 00:00 0 [vdso]
ffffffffff600000-ffffffffff601000 r-xp 00000000 00:00 0 [vsyscall]
Aborted
我不知道油嘴滑舌是什么意思,但我看不出我在哪里有双重自由。当我注释掉Student析构函数时,代码运行良好。为什么?我已经为每门课程分配了内存,所以我在析构函数中释放了内存,因此我认为没有它程序就无法运行,但它确实可以。编辑:还有一件事。当我评论学生二=一时,没有什么区别;行,所以我猜错误在addCourse()和/或析构函数中
很抱歉这是一个很长的问题非常感谢SO
您的赋值运算符出现问题:
Student &operator=(const Student &s) {
cout << "Assigning student" << endl;
id = s.id;
for (int i = 0; i < 5; i++) {
courses[i] = s.courses[i];
}
return *this;
}
您复制原始指针而不是对象,然后两个单独的Student
对象拥有相同的Course
对象,因此第二个Student
的析构函数第二次销毁相同的Course
。也许你想要:
*(courses[i]) = *(s.courses[i]);
相反。
正如其他答案所指出的,您的赋值运算符不正确。
然而,为了容易地解决您的问题,只需使用copy / swap
,因为您已经为类编码了一个复制构造函数和析构函数:
#include <algorithm>
//...
Student &operator=(const Student &s)
{
cout << "Assigning student" << endl;
Student temp(s);
std::swap(temp.id, id);
std::swap(temp.courses, courses);
return *this;
}
我们只是从传入的Student
创建了一个临时Student
副本,然后用临时成员交换了当前学生的内部成员。同样,这只能与Student
(您已经提供)的工作副本构造函数和析构函数一起使用。
另一个问题是addCourse
函数。问题是,您为它提供了指向而不是动态分配的对象的指针。当析构函数被调用时,它假设所有指针都来自对new
的调用,而事实并非如此。
void addCourse(Course *c) {
delete courses[size];
courses[size] = c;
size++;
}
~Student() {
for (int i = 0; i < 5; i++) {
delete courses[i]; // <-- Assumes all courses were allocated dynamically
}
}
//...
Course cs246("cs246");
Course cs245("cs245");
one.addCourse(&cs246); // <-- Not allocated with new
one.addCourse(&cs245); // <-- Not allocated with new
这是你设计中的一个缺陷。要么通过对main
大喊大叫来拒绝
不要这样做,我只接受用new
"分配的东西,并且有这样的代码:
Course* cs246 = new Course("cs246");
Course* cs245 = new Course("cs245");
one.addCourse(cs246);
one.addCourse(cs245);
实际示例
或
参考课程并复制(类似于vector
的工作方式),并在课堂上自己管理记忆。
void addCourse(const Course& c)
{
delete courses[size];
Course* temp = new Course(c);
courses[size] = temp;
size++;
}
//...
Course cs246("cs246");
Course cs245("cs245");
one.addCourse(cs246);
one.addCourse(cs245);
实例
在Student &operator=(const Student &s)
中,您正在从s
复制指向课程的指针,因此您会得到双重删除。
我相信,出于家庭作业的目的,你可以像复制构造函数中那样做——创建具有相同名称的新课程。