如何在mvc.net中刷新提交视图

Question

我得到了以下函数

function success(result)
{
    $("#Div2").html(result);       
    reloadDisplayAverage();        
}
function reloadDisplayAverage()
{       
    var tdata = $('#form').serialize();
    $.ajax({
        type: "POST",
        data: {
            mCollection: tdata,
        },
        url: "Search/SearchMenu",
        success: function (result) { success(result);
    });
function success(result)
{       
    $("#Div1").html(result);
}

我有我的提交按钮

<div id="Div2">
    <input type="submit" /> 
</div> 

然后我有一个空的div

<div id="Div1"> </div>, 

当我调试时，我在控制器中得到了正确的结果，现在我不知道该把结果放在视图中；。

在我的控制器中，我正在使用

  public ActionResult SearchMenu(SVM svm)
    {
        var sv = qr.QueryResult(svm);
         return view() // If I pass like this, I won't get result back to                     view 
      // return View(sv) If I pass like this, it won't be valid model for the view as in view is tightly bounded to SVM 
    }

Answer 1

开始：

HTML:

<div id="Div1"></div>  <!--Your result view goes here!!!-->
<button type="button" id="yourButtonId">Post</button>

JQuery:

$("#yourButtonID").click(function(){
    function reloadDisplayAverage() {       
        var tdata = $('#form').serialize();
        $.ajax({
            type: "POST",
            data: tdata,
            url: "Search/SearchMenu",
            success: function (result) { 
            $("#Div1").html(result);
           }
        });                  
      }
});

希望它能有所帮助；）