从 JSON 字符串 Javascript 中删除外部索引

Question

我在JavaScript中有以下JSON字符串：

{
 "0":
   {"race":"Race1","sum":"13.7","color":"#BEBEBE"},
 "1":
   {"race":"Race2","sum":"20.3","color":"#B03060"},
 "2":
   {"race":"Race3","sum":"35.2","color":"#FFFF01"},
 "3":
   {"race":"Race4","sum":"31.3","color":"#4A6FE3"},
 "4":
   {"race":"Unknown","sum":0,"color":"#9ACD32"}
}

我需要转换为：

编辑的示例

[{"race":"Race1","sum":"13.7","color":"#BEBEBE"},
  {"race":"Race2","sum":"20.3","color":"#B03060"},
  {"race":"Race3","sum":"35.2","color":"#FFFF01"},
  {"race":"Race4","sum":"31.3","color":"#4A6FE3"},
  {"race":"Unknown","sum":0,"color":"#9ACD32"}]

有什么方法可以实现吗？

Answer 1

您可以简单地解析并获取这样的值。

var jsonStr = '{"0":{"race":"Race1","sum":"13.7","color":"#BEBEBE"},"1":{"race":"Race2","sum":"20.3","color":"#B03060"},"2":{"race":"Race3","sum":"35.2","color":"#FFFF01"},"3":{"race":"Race4","sum":"31.3","color":"#4A6FE3"},"4":{"race":"Unknown","sum":0,"color":"#9ACD32"}}';
var json = Object.values(JSON.parse(jsonStr));
console.log(json)

Answer 2

您可以在没有键的对象中拥有对象，您应该将它们保留在数组中或处于原始状态

如果要修改，请使用Object.key(obj)，然后遍历所有键

var obj = {
 "0":
   {"race":"Race1","sum":"13.7","color":"#BEBEBE"},
 "1":
   {"race":"Race2","sum":"20.3","color":"#B03060"},
 "2":
   {"race":"Race3","sum":"35.2","color":"#FFFF01"},
 "3":
   {"race":"Race4","sum":"31.3","color":"#4A6FE3"},
 "4":
   {"race":"Unknown","sum":0,"color":"#9ACD32"}
}
var arr = [];
Object.keys(obj).forEach(function(item) {
  arr.push(obj[item]);
})
console.log(arr);

或者按照@trincot的建议使用地图

var obj = {
 "0":
   {"race":"Race1","sum":"13.7","color":"#BEBEBE"},
 "1":
   {"race":"Race2","sum":"20.3","color":"#B03060"},
 "2":
   {"race":"Race3","sum":"35.2","color":"#FFFF01"},
 "3":
   {"race":"Race4","sum":"31.3","color":"#4A6FE3"},
 "4":
   {"race":"Unknown","sum":0,"color":"#9ACD32"}
}
var arr = Object.keys(obj).map(function(item) {
  return obj[item]
})
console.log(arr);

然而，最简单的使用Object.values(obj)

var obj = {
 "0":
   {"race":"Race1","sum":"13.7","color":"#BEBEBE"},
 "1":
   {"race":"Race2","sum":"20.3","color":"#B03060"},
 "2":
   {"race":"Race3","sum":"35.2","color":"#FFFF01"},
 "3":
   {"race":"Race4","sum":"31.3","color":"#4A6FE3"},
 "4":
   {"race":"Unknown","sum":0,"color":"#9ACD32"}
}

console.log(Object.values(obj));

Answer 3

使用 object.values() 函数：

let f= 
{
 "0":
   {"race":"Race1","sum":"13.7","color":"#BEBEBE"},
 "1":
   {"race":"Race2","sum":"20.3","color":"#B03060"},
 "2":
   {"race":"Race3","sum":"35.2","color":"#FFFF01"},
 "3":
   {"race":"Race4","sum":"31.3","color":"#4A6FE3"},
 "4":
   {"race":"Unknown","sum":0,"color":"#9ACD32"}
}

Console.log(Object.values(f))输出 ：

[ { race: 'Race1', sum: '13.7', color: '#BEBEBE' },
  { race: 'Race2', sum: '20.3', color: '#B03060' },
  { race: 'Race3', sum: '35.2', color: '#FFFF01' },
  { race: 'Race4', sum: '31.3', color: '#4A6FE3' },
  { race: 'Unknown', sum: 0, color: '#9ACD32' } ]