参考
当我试图用字符串输入模拟静态方法时,当我给出特定的字符串时,模拟的存根将被执行,但是当我使用Anystring((时,它不起作用正如预期的。
public class Foo {
public static String staticInput(String s) {
System.out.println("staticInput called");
return "static " + s;
}
}
@RunWith(PowerMockRunner.class)
@PrepareForTest({Foo.class})
public class TestMockito {
@Test
public void test1() throws Exception {
PowerMockito.spy(Foo.class);
PowerMockito.doReturn("dummyStaticStub").when(Foo.class, "staticInput", "1");
System.out.println(Foo.staticInput("1"));
}
@Test
public void test2() throws Exception {
PowerMockito.spy(Foo.class);
PowerMockito.doReturn("dummyStaticIn").when(Foo.class, "staticInput", anyString());
System.out.println(Foo.staticInput("1"));
}
}
test1打印:
dummystaticstub
test2打印:
称为
的静态图 静态1
您可以稍微更改该方法并使用PowerMockito.mockStatic
代替
@RunWith(PowerMockRunner.class)
@PrepareForTest({Foo.class})
public class TestMockito {
@Test
public void test1() throws Exception {
PowerMockito.mockStatic(Foo.class);
Mockito.when(Foo.staticInput("1")).thenReturn("dummyStaticStub");
System.out.println(Foo.staticInput("1"));
}
@Test
public void test2() throws Exception {
PowerMockito.mockStatic(Foo.class);
PowerMockito.when(Foo.staticInput(anyString())).thenReturn("dummyStaticIn");
System.out.println(Foo.staticInput("1"));
}
}
使用PowerMock与Mockito:Mocking静态方法