空格和选项卡比较字符串XCode

Question

我写了简单的测试：

   func testTabs() {
        let tabbed = "t"
        let spaced = "    "
        XCTAssert(tabbed == spaced, "Comparison is illegal")
    }
   func testTabs() {
        let tabbed = "t"
        let tab = "    "
        XCTAssert(tabbed == tab, "Comparison is illegal")
    }

如果使用实际'选项卡'间距失败，对于4个空间，2个空间，它失败了。因此，我比较 TAB for t ，它失败了。(对于任何等效物也失败(。

它应该可以工作吗？如果我想做测试，我应该在字符串中切勿在字符串中使用 tab ？让我表明我的意思：

func generateSomeString() -> String {
    let array = ["Some","Stupid","People","Don't","Read","But","Comment"]
    let string = array.joined(separator: "t")
    return string
}
func testStrings() {
    let string = generateSomeString()
    let expectedString = "Some    Stupid    People    Don't    Read    But    Comment"
    print(string)
    XCTAssert(string == expectedString, "Comparison is illegal")
}

Answer 1

选项卡和空格是空格，但不是同一回事。

您可以将t替换为预期数量的空间，然后对其进行测试...