从构造的名称中获取Swift变量的值

Question

我遇到了一个问题，我正试图在Swift 4中解决这个问题。

比方说，我有以下变量

let var1 = "One"
let var2 = "Two"
let var3 = "Three"
var counter = 1
// Loop Start
let currentVariable = "var" + "(counter)"
//Fetch the value of variable stored under currentVariable
counter += 1
//Loop end

我正在尝试根据存储在currentVariable下的变量名称获取值。

Answer 1

您可以设置dictionary，用键替换变量名。

let letters = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
var myDictionary:[String:String] = ["var1":"One", "var2":"Two", "varA":"A", "varB":"B"]  // note, both sides can be different types than String
for x in 0...9 {
let myKey = "var" + String(x)
printValue(myKey)
}
for x in letters.characters {
let myKey = "var" + String(x)
printValue(myKey)
}

简单的功能：

func printValue(_ key:String) {
let myValue = myDictionary[key]
if myValue != nil {
print(myValue)
}
}

我很确定你可以把东西做得更优雅一点，但你明白了。另外，请记住Dictionary是"无序的"，而不是数组。

Answer 2

使用数组

let myArray = ["one", "two", "three"];
var counter = 1;
print(myArray[counter]);