尝试在sklearn中创建一个左右离散的HMM来识别来自识别字符的单词。 符号集是所有 " " + 26 个字母,总共 27 个符号。
import numpy as np
from sklearn import hmm
# alphabet is symbols
symbols = [' ','a','b','c','d','e','f','g','h','i','j', #0-10
'k','l','m','n','o','p','q','r','s','t', #11-20
'u','v','w','x','y','z'] #21-26
num_symbols = len(symbols)
# words up to 6 letters
n_states = 6
obsONE = np.array([ [0,0,15,14,5,0], # __one_
[15,14,5,0,0,0], # one___
[0,0,0,15,14,5], # ___one
[0,15,14,5,0,0], # _one__
[0,0,16,14,5,0], # __pne_
[15,14,3,0,0,0], # onc___
[0,0,0,15,13,5], # ___ome
[0,15,14,5,0,0], # _one__
[0,0,15,14,5,0], # __one_
[15,14,5,0,10,15], # one_jo
[1,14,0,15,14,5], # an_one
[0,15,14,5,0,16], # _one_p
[20,0,15,14,5,0], # t_one_
[15,14,5,0,10,15], # one_jo
[21,20,0,15,14,5], # ut_one
[0,15,14,5,0,20], # _one_t
[21,0,15,14,5,0], # u_one_
[15,14,5,0,10,15], # one_jo
[0,0,0,15,14,5], # an_one
[0,15,14,5,0,26], # _one_z
[5,20,0,15,14,5] ])
pi = np.array([1.0, 0.0, 0.0, 0.0, 0.0, 0.0]) # initial state is the left one always
A = np.array([[0.0, 1.0, 0.0, 0.0, 0.0, 0.0], # node 1 goes to node 2
[0.0, 0.5, 0.5, 0.0, 0.0, 0.0], # node 2 can self loop or goto 3
[0.0, 0.0, 0.5, 0.5, 0.0, 0.0], # node 3 can self loop or goto 4
[0.0, 0.0, 0.0, 0.5, 0.5, 0.0], # node 4 can self loop or goto 5
[0.0, 0.0, 0.0, 0.0, 0.5, 0.5], # node 5 can self loop or goto 6
[1.0, 0.0, 0.0, 0.0, 0.0, 0.0]]) # node 6 goes to node 1
model = hmm.MultinomialHMM(n_components=n_states,
startprob=pi, # this is the start matrix, pi
transmat=A, # this is the transition matrix, A
params='e', # update e in during training (aka B)
init_params='ste') # initialize with s,t,e
model.n_symbols = num_symbols
model.fit(obsONE)
但是我得到 ValueError:输入必须既是正整数数组,又必须是连续的。
代码似乎直接希望将观察实现为 [0,1,2,3,4,5]
我应该如何设置它才能获得我想要的 HMM 模型???
我遇到了同样的问题。在我看来,输入的观察序列不包含词汇表中的某些字符。因此,您可以在找出观察序列中存在哪些字符后为字符分配数字,而不是静态地为它们分配数字。
(例如。假设单词 = 'apzaqb'
用
符号 = ['a','b','p','q','z'] 用于编号
(即)ObsOne = np.array([0,2,4,0,3,1])
而不是
符号 = ['','a','b','c','d','e','f','g','h','i','j','k','l','m','n',o','p','q','r',s't','u','v','w','x','y','z'] 用于编号
(即)ObsOne = np.array([1,16,26,1,17,2])