我已经设法用php和ajax填充了我的三个下拉列表。这是我代码中显示三个下拉列表的一部分:
<?php
echo "<font id="categoria"><select>n";
echo "<option value='0'>Select the Firm</option> n" ;
echo "</select></font>n";
?>
<?php
echo "<font id="subcategoria"><select>n";
echo "<option value='0'>Select the Claims Hub</option> n" ;
echo "</select></font>n";
?>
<?php
echo "<font id="subcategoria2"><select>n";
echo "<option value='0'>Select the Area</option> n" ;
echo "</select></font>n";
?>
我的问题是:我在这些页面上还有一个表单,我想把三个下拉列表作为我表单的一部分,以便将值发布到另一个mysql表中。有什么建议我该怎么做吗?这是我的表单部分:
<form method="post" align= "right">
<table >
<tr><td> </td>
<tr>
<td>Select the Matter Type: </td>
<td><?php echo $dropdown; ?></td>
</tr>
<tr><td> </td>
<tr>
<td style="text-align: left; ">Active </td>
<td align="left" >
<input type="checkbox" name="active" value="1" />
</td>
</tr>
<tr><td> </td>
<tr>
<td> </td>
<td><input type="submit" name="submit" value="Add" align= "right" /></td>
</tr>
</table>
为什么不直接将它们插入到html中呢?
<form method="post" align= "right">
<table >
<tr><td> </td>
<tr>
<td>Select the Matter Type: </td>
<td><?php echo $dropdown; ?></td>
</tr>
<tr>
<td>
<?php echo "<font id="categoria"><select><option value='0'>Select the Firm</option></select></font>";?>
</td>
</tr>
<tr><td> </td>
<tr>
<td style="text-align: left; ">Active </td>
<td align="left" >
<input type="checkbox" name="active" value="1" />
</td>
</tr>
<tr><td> </td>
<tr>
<td> </td>
<td><input type="submit" name="submit" value="Add" align= "right" /></td>
</tr>