换行符不起作用-Python

Question

不知怎么的，换行符没有正常工作。这就是我得到的：

Expected:
    O meu u2 2 post
    http://www.yahoo.com
    1 Gosto, 0 Nao gosto
    <BLANKLINE>
    O meu u2 post
    http://www.altavista.com
    1 Gosto, 0 Nao gosto
Got:
    'O meu u2 2 postnhttp://www.yahoo.comn1 Gosto, 0 Nao GostonnO meu u2nhttp://www.yahoo.comn1 Gosto, 0 Nao Gosto'

这是函数中使用的代码。重要的部分应该是str和showRecentComments函数

class Comments():
def __init__(self, u=None, text='', link=None):
    self.u = u
    self.text = text
    self.link = link
    self.topo = None
    self.fim = None
def __str__(self):
    actual = self.topo
    s = ''
    if actual == None:
        return None
    while actual != None:
        if actual.seg == None:
            s += str(actual)
            actual = actual.seg
        else:
            s += str(actual) + 'n' + 'n'
            actual = actual.seg
    return s
def add(self,comment):
    if self.topo == None:
        self.topo = comment
        self.fim = comment
    else:
        comment.seg = self.topo
        self.topo.ant = comment
        self.topo = comment
def remove(self,comment):
    actual = self.topo
    if (self.topo == self.fim) and (self.topo == comment):
        self.topo = None
        self.fim = None
    while actual!=None:
        if actual == comment:
            if self.topo==comment:
                actual.seg.ant = None
                self.topo = actual.seg
            elif self.fim==comment:
                actual.ant.seg = None
                self.fim = actual.ant
            else:
                actual.seg.ant = actual.ant
                actual.ant.seg = actual.seg
            break
        else:
            actual = actual.seg
def countLike(self):
    count = 0
    actual = self.topo
    while actual != None:
        if len(actual.likeList) >= 1:
            count += 1
            actual = actual.seg
        else:
            actual = actual.seg
    return count
def showRecentComments(self,n):
    count = 1
    actual = self.topo
    sC = ''
    if actual == None:
        return None
    while actual != None:
        if count < n:
            sC += str(actual) + 'n' + 'n'
            count += 1
            actual = actual.seg
        elif count == n:
            sC += str(actual)
            count += 1
            actual = actual.seg
        elif count > n:
            break 
    return sC

此致，Nelson Gregório

Answer 1

看起来您正在查看字符串的表示形式，它将以n的形式显示换行符。如果您将字符串print或写入stdout（sys.stdout.write(s)），则换行符将被展开。