>假设 .NET 解决方案中有两个项目:
Solution
- Project1
- Project2
我只想从项目2到项目1 Project References
,例如:
<ItemGroup>
<ProjectReference Include="Project1.csproj" />
</ItemGroup>
但有时开发人员会添加错误的File References
,例如:
<ItemGroup>
<Reference Include="Project1">
<HintPath>pathtoProject1.dll</HintPath>
</Reference>
</ItemGroup>
如何确定解决方案项目之间没有File References
?理想情况下,它应该是一个构建错误,但实现它的最佳方法是什么?
我找到了解决方案。可以添加MSBuild
任务(目标),以检查所有解决方案项目中的文件引用。必须将此任务添加到所有项目或Directory.Build.targets
中。这是目标:
<Project>
<Target Name="BeforeBuild">
<Message Text="Analyzing '$(MSBuildProjectFile)' for file references between solution projects...
" />
<GetSolutionProjects Solution="$(MSBuildThisFileDirectory)YourSolutionName.sln">
<Output ItemName="Projects" TaskParameter="Output"/>
</GetSolutionProjects>
<PropertyGroup>
<Expression>(@(Projects->'%(ProjectName)', '|')).dll</Expression>
</PropertyGroup>
<XmlRead XmlFileName="$(MSBuildProjectFile)" XPath="//Project/ItemGroup/Reference/HintPath">
<Output ItemName="FileReferences" TaskParameter="Value"/>
</XmlRead>
<RegexMatch Input="@(FileReferences)" Expression="$(Expression)">
<Output TaskParameter="Output" ItemName ="ProjectReferences" />
</RegexMatch>
<Error Text="There must be no file references between solution projects, but it was found in '$(MSBuildProjectFile)' to the following file(s): %(ProjectReferences.Identity)"
Condition="'%(ProjectReferences.Identity)' != ''" />
</Target>
</Project>
此目标使用 MSBuild 社区任务,因此不要忘记将此 NuGet 包添加到所有项目(或Directory.Build.props
)。
你可以写一个简单的PowerShell
$path = "D:tempSolution1"
$extension = "csproj"
#-------------------
$projects = Get-ChildItem -Path $path -Recurse -Filter "*.$($extension)"
$projectsList = @()
# Create the project's solution list
foreach ($project in $projects)
{
$projectsList += $project
}
foreach($project in $projectsList)
{
# Read the project xml
[xml]$proj = [System.IO.File]::ReadAllText($project.FullName)
# loop throught ItemGroup
foreach($item in $proj.Project.ItemGroup)
{
# Looking for project reference
$all = $projectsList | where {$_.Name -eq "$($item.Reference.Include).$($extension)"}
foreach($ref in $all)
{
Write-Warning "Find wrong reference for $($ref.Name) on $($project.Name)"
}
}
}