Sample models.py
models.py
class Food(models.Model):
name = models.CharField(max_length=50, verbose_name='Food')
def __str__(self):
return self.name
假设我编写了单元测试：
from django.test import TestCase
from myapp.models import Food
class TestWhateverFunctions(TestCase):
"""
This class contains tests for whatever functions.
"""
def setUp(self):
"""
This method runs before the execution of each test case.
"""
Food.objects.create(name='Pizza') # Will the created object have id of 1?
Food.objects.create(name='Pasta') # Will the created object have id of 2?
def test_if_food_is_pizza(self):
"""
Test if the given food is pizza.
"""
food = Food.objects.get(id=1)
self.assertEqual(food.name, 'Pizza')
def test_if_food_is_pasta(self):
"""
Test if the given food is pasta.
"""
food = Food.objects.get(id=2)
self.assertEqual(food.name, 'Pasta')
我想知道假设setUp(( 方法中创建的对象的 id 将始终从id 1开始是否安全，依此类推？如果不是，是否有特定原因导致在运行所有测试后始终销毁测试数据库？
假设 id 总是从1 开始并递增是不安全的。如果其他测试事先运行并创建了Food行，并且单元测试未按任何保证顺序执行，则它们可能具有更高的 ID。
在测试设置中保存对模型实例的引用：
class TestWhateverFunctions(TestCase):
def setUp(self):
self.food1 = Food.objects.create(name='Pizza')
self.food2 = Food.objects.create(name='Pasta')
谢谢你的好例子。对于像我这样的新手，我随后使用了：
self.food1.id
作为测试 URL 的请求和响应的主键。