如何使用 python/bash 脚本列出 Centos7 中所有超过 "X" 小时的文件？

Question

如何在 Centos7 中使用 python 脚本或 bash 脚本列出所有早于 "X" 小时的文件？

很多谢谢！

Answer 1

你可以使用 GNU find 命令：

find [path] -mmin +[minutes]

示例：查找 2 小时内/超过 2 小时的所有文件：

find / -mmin +120

Answer 2

您可以使用find命令：

find <path> <conditions> <actions>

文件类型条件：

-type f            # File
-type d            # Directory
-type l            # Symlink

访问时间条件 ：

-atime 0           # Last accessed between now and 24 hours ago
-atime +0          # Accessed more than 24 hours ago
-atime 1           # Accessed between 24 and 48 hours ago
-atime +1          # Accessed more than 48 hours ago
-atime -1          # Accessed less than 24 hours ago (same a 0)
-ctime -6h30m      # File status changed within the last 6 hours and 30 minutes
-mtime +1w         # Last modified more than 1 week ago

行动：

-exec rm {} ;
-print
-delete

你也可以处理大小：

-size 8            # Exactly 8 512-bit blocks 
-size -128c        # Smaller than 128 bytes
-size 1440k        # Exactly 1440KiB
-size +10M         # Larger than 10MiB
-size +2G          # Larger than 2GiB

例子：

find . -type f ctime -6h30m # File status changed within the last 6 hours and 30 minutes
find . -type f -mtime +29 # find files modified more than 30 days ago