Android MediaPlayer seekBar 無法正常工作

Question

目前，我正在开发一个媒体播放器，我需要seekBar一起工作，目前，一切都很好！ 但是，当我触摸搜索栏的确定位置时，媒体播放器必须跟随并将歌曲设置为这个确定的位置，但是歌曲和 seekBar回到起点，我不知道为什么会发生这种情况。

主活动.java

public class MainActivity extends AppCompatActivity {
private Handler mHandler = new Handler();
public TextView song_detail;
public TextView time1;
public TextView time2;
private String player_status = "playing";
private ImageButton player_img;
public static SeekBar seekBar;
private static MediaPlayer mediaPlayer;
@SuppressLint("RestrictedApi")
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
song_detail = findViewById(R.id.song_detail);
song_detail.setVisibility(View.GONE);
time1 = findViewById(R.id.time_1);
time2 = findViewById(R.id.time_2);
seekBar = findViewById(R.id.seekBar);
final Runnable mRunnable = new Runnable() {
@Override
public void run() {
if(mediaPlayer != null){
int CurrentPosition = mediaPlayer.getCurrentPosition();
String m_1;
String s_1;
seekBar.setProgress(CurrentPosition/1000);
final int minutes_1 = (CurrentPosition/1000)/60;
final int seconds_1 = ((CurrentPosition/1000)%60);
if (minutes_1 < 10) {
m_1 = "0" + minutes_1;
} else {
m_1 = "" + minutes_1;
}
if (seconds_1 < 10) {
s_1 = "0" + seconds_1;
} else {
s_1 = "" + seconds_1;
}
time1.setText(m_1 + ":" + s_1);

int Duration = mediaPlayer.getDuration();
String m_2;
String s_2;
final int minutes_2 = (Duration/1000)/60;
final int seconds_2 = ((Duration/1000)%60);
if (minutes_2 < 10) {
m_2 = "0" + minutes_2;
} else {
m_2 = "" + minutes_2;
}
if (seconds_2 < 10) {
s_2 = "0" + seconds_2;
} else {
s_2 = "" + seconds_2;
}
time2.setText(m_2 + ":" + s_2);
}
mHandler.postDelayed(this, 1000);
}
};
mRunnable.run();

seekBar.setOnSeekBarChangeListener(new SeekBar.OnSeekBarChangeListener() {
@Override
public void onProgressChanged(SeekBar seekBar, int progress, boolean fromUser) {
if(mediaPlayer != null && fromUser){
Toast.makeText(getApplicationContext(), String.valueOf(progress), Toast.LENGTH_LONG).show();
mediaPlayer.seekTo(progress);
seekBar.setProgress(progress);
}
}
@Override
public void onStartTrackingTouch(SeekBar seekBar) { }
@Override
public void onStopTrackingTouch(SeekBar seekBar) { }
});
}
public void initAudio(final Context context, final String url) {
if (mediaPlayer == null) {
mediaPlayer = MediaPlayer.create(context, Uri.parse(url));
}
mediaPlayer.setOnCompletionListener(new MediaPlayer.OnCompletionListener() {
@Override
public void onCompletion(MediaPlayer mp) {
//Toast.makeText(context, "TEST", Toast.LENGTH_LONG).show();
killMediaPlayer();
}
});
seekBar.setMax(mediaPlayer.getDuration()/1000);
mediaPlayer.start();
}
public void killMediaPlayer() {
if (mediaPlayer != null) {
try {
mediaPlayer.reset();
mediaPlayer.release();
mediaPlayer = null;
} catch (Exception e) {
e.printStackTrace();
}
}
}

public static void pauseAudio() {
if (!(mediaPlayer == null)) {
mediaPlayer.pause();
}
}
public static void startAudio() {
if (!(mediaPlayer == null)) {
mediaPlayer.start();
}
}
}

这是我用来处理mediaPlayer和seekBar的代码部分

。

seekBar.setOnSeekBarChangeListener(new SeekBar.OnSeekBarChangeListener() {
@Override
public void onProgressChanged(SeekBar seekBar, int progress, boolean fromUser) {
if(mediaPlayer != null && fromUser){
Toast.makeText(getApplicationContext(), String.valueOf(progress), Toast.LENGTH_LONG).show();
mediaPlayer.seekTo(progress);
seekBar.setProgress(progress);
}
}
@Override
public void onStartTrackingTouch(SeekBar seekBar) { }
@Override
public void onStopTrackingTouch(SeekBar seekBar) { }
});
}

但正如我所说，与其让媒体播放器从我单击的位置寻找并继续音频，不如简单地将音频返回到起点。我做错了什么？

谢谢。

Answer 1

progress的最大值为 100。seekTo函数以毫秒为单位花费时间。这就是为什么它寻求音频的开始(几乎(。

所以与其mediaPlayer.seekTo(progress);，你需要做的是：

long newTime = (progress/100.0) * total_audio_duration_in_millisecond; 
mediaPlayer.seekTo(newTime);