我的网站上有一个侧菜单,目前是一个列表项的负载:
<ul>
<li>...</li>
<li>...</li>
<li>...</li>
</ul>
现在我需要改变这个有子项,所以它呈现…
<ul>
<li>
<ul>
<li>...</li>
<li>...</li>
</ul>
</li>
<li>...</li>
<li>...</li>
</ul>
我有一个项目列表,如下所示:
/// <summary>
/// Gets the admin menu items.
/// </summary>
/// <returns></returns>
public IQueryable<IAdminMenuItem> GetAdminMenuItems()
{
return new List<IAdminMenuItem> {
new AdminMenuItem {MenuItemId = "100", DisplayText = "xxx", ParentId = "" ControllerName = "xxx", ActionName = "xxx"},
new AdminMenuItem {MenuItemId = "101", DisplayText = "xxx", ParentId = "100" ControllerName = "xxx", ActionName = "xxx"},
new AdminMenuItem {MenuItemId = "102", DisplayText = "xxx", ParentId = "100" ControllerName = "xxx", ActionName = "xxx"},
new AdminMenuItem {MenuItemId = "200", DisplayText = "xxx", ParentId = "" ControllerName = "xxx", ActionName = "xxx"},
new AdminMenuItem {MenuItemId = "201", DisplayText = "xxx", ParentId = "200" ControllerName = "xxx", ActionName = "xxx"},
new AdminMenuItem {MenuItemId = "202", DisplayText = "xxx", ParentId = "200" ControllerName = "xxx", ActionName = "xxx"},
}.AsQueryable();
如果列表项没有ParentID,则它是顶级元素。如果是,则为子项元素。
我现在已经有了这个代码来处理平面菜单结构:
<ul>
@foreach (Avelo.Exchange.WebUI.Domain.Interfaces.IAdminMenuItem item in Model){
<li><a href="@Url.Action(item.ActionName, item.ControllerName)"><span>@item.DisplayText</span></a></li>
}
</ul>
我想我的第一个问题是我如何处理视图中的子菜单项,但我也想通过它能够处理进一步的子级别(即三个步骤而不是两个)来证明未来的解决方案。我听说过递归循环,但不知道如何实现它。这是个好办法吗?
Thanks in advance
S
我以前也遇到过类似的问题。我将设法使我的解适合你的模型。我猜你是这样写的:
public interface IAdminMenuItem
{
string MenuItemId { get; set; }
string DisplayText { get; set; }
string ControllerName { get; set; }
string ActionName { get; set; }
List<IAdminMenuItem> Children { get; set; }
}
public class AdminMenuItem: IAdminMenuItem
{
public string MenuItemId { get; set; }
public string DisplayText { get; set; }
public string ControllerName { get; set; }
public string ActionName { get; set; }
public List<IAdminMenuItem> Children { get; set; }
}
你可以看到,我已经改变了你的属性ParentId与儿童的集合,因为它更容易管理。
在您的视图中,您将填充您的菜单(和所有子菜单)并将其传递给视图:
List<IAdminMenuItem> myMenu = new List<IAdminMenuItem>();
myMenu.Add(new AdminMenuItem()
{
MenuItemId = "100",
DisplayText = "Level 1",
ControllerName = "Home",
ActionName = "Index",
Children = new List<IAdminMenuItem>() {
new AdminMenuItem() { MenuItemId = "1001", DisplayText = "Level 1a", ControllerName = "Home", ActionName = "Index" },
new AdminMenuItem() { MenuItemId = "1002", DisplayText = "Level 1b", ControllerName = "Home", ActionName = "Index" }
}
});
myMenu.Add(new AdminMenuItem()
{
MenuItemId = "200",
DisplayText = "Level 2",
ControllerName = "Home",
ActionName = "Index",
Children = new List<IAdminMenuItem>() {
new AdminMenuItem() { MenuItemId = "2001", DisplayText = "Level 2a", ControllerName = "Home", ActionName = "Index" },
new AdminMenuItem() { MenuItemId = "2002", DisplayText = "Level 2b", ControllerName = "Home", ActionName = "Index" }
}
});
return View(myMenu);
这是我的观点。这里的东西不多。
@using Mvc3SubMenus.WebUI
@model List<Mvc3SubMenus.IAdminMenuItem>
@{
ViewBag.Title = "Home Page";
}
@Html.BuildMenu(Model)
我已经创建了一个助手,它将负责创建您的菜单和所有子菜单(递归):
using System.Collections.Generic;
using System.Web.Mvc;
using System.Text;
using System.Web.Mvc.Html;
namespace Mvc3SubMenus.WebUI
{
public static class MyHelpers
{
public static System.Web.Mvc.MvcHtmlString BuildMenu(this HtmlHelper helper, List<Mvc3SubMenus.IAdminMenuItem> menu)
{
return new MvcHtmlString(BuildStringMenu(helper, menu));
}
private static string BuildStringMenu(HtmlHelper helper, List<Mvc3SubMenus.IAdminMenuItem> menu)
{
var sb = new StringBuilder();
if ((menu != null) && (menu.Count > 0))
{
sb.Append("<ul>");
foreach (var item in menu)
{
sb.Append("<li>");
sb.Append(helper.ActionLink(item.DisplayText, item.ActionName, item.ControllerName));
sb.Append("</li>");
if ((item.Children != null) && (item.Children.Count > 0))
{
sb.Append("<li>");
sb.Append(BuildStringMenu(helper, item.Children));
sb.Append("</li>");
}
}
sb.Append("</ul>");
}
return (sb.ToString());
}
}
}
这个助手可以改进,当然有人可能会反对它可以用更好的方式完成,但我没有太多的时间来完善它。很抱歉。
您可以在这里找到一些代码。项目名为Mvc3SubMenus