Sudzc 反序列化为字典:覆盖书面字典

Question

Sudzc生成的代码正在为反序列化节点编写字典。 如果我使用 NSLog（@"The Child Node： %@"， [[element children] objectAtIndex：0] stringValue]）;每次通过时，它都会写出正确的项目。 当我尝试在代码中检索结果时，只有最后一个可用（杰克逊 3）。 我做错了什么？

// Deserializes the element in a dictionary.
+(id)deserializeAsDictionary:(CXMLNode*)element {
if([element childCount] == 1) {
    CXMLNode* child = [[element children] objectAtIndex:0];
    if([child kind] == CXMLTextKind) 
    {
         NSLog(@"The Child Node: %@", [[[element children] objectAtIndex:0] stringValue]);
        return [[[element children] objectAtIndex:0] stringValue];
    }
}
NSMutableDictionary* d = [NSMutableDictionary dictionary];
for(CXMLNode* child in [element children]) {
    id v = [Soap deserialize:child];
    if(v == nil) { v = [NSNull null]; }
    [d setObject:v forKey:[child name]];
}
return d;
}

NSLog：

2012-04-19 14:13:07.802 Management[3043:10703] Hopefully Child: Allen
2012-04-19 14:13:07.803 Management[3043:10703] Hopefully Child: 1
2012-04-19 14:13:07.804 Management[3043:10703] Hopefully Child: John
2012-04-19 14:13:07.804 Management[3043:10703] Hopefully Child: 2
2012-04-19 14:13:07.805 Management[3043:10703] Hopefully Child: Jackson
2012-04-19 14:13:07.805 Management[3043:10703] Hopefully Child: 3

.XML：

<TC diffgr:id="TC1" msdata:rowOrder="0">
 <CSHR_POS_NAME>Allen</CSHR_POS_NAME>                            
    <CSHR_NUM>66</CSHR_NUM>
</TC>
<TC diffgr:id="TC2" msdata:rowOrder="1">                                    
  <CSHR_POS_NAME>John</CSHR_POS_NAME>
    <CSHR_NUM>2</CSHR_NUM>
    </TC>
<TC diffgr:id="TC3" msdata:rowOrder="2">
<CSHR_POS_NAME>Jackson</CSHR_POS_NAME>
<CSHR_NUM>3</CSHR_NUM>
</TC>

Answer 1

已解决（更改了 soap.m）：

[d setObject:v forKey:[child name]]; 
NSString* key = [child name]; 
id check = [d objectForKey:key]; 
if( check != nil ) { 
    NSInteger next = 1; 
    key = [NSString stringWithFormat:@"%@%d", [child name], next]; 
    check = [d objectForKey:key]; 
    while( check != nil ) { 
        next++; 
        key = [NSString stringWithFormat:@"%@%d", [child name], next]; 
        check = [d objectForKey:key]; 
    } 
    [d setObject:v forKey:key]; 
} 
[d setObject:v forKey:[child name]]; 

Answer 2

只要

我得到足够的代表点，我就会这样做，但我确实注意到代码的开头和结尾都是

  [d setObject:v forKey:[child name]];

对我来说，我

必须删除初始行，这为我修复了它，所以代码看起来像这样：

// Deserializes the element in a dictionary.
 +(id)deserializeAsDictionary:(CXMLNode*)element {
if([element childCount] == 1) {
    CXMLNode* child = [[element children] objectAtIndex:0];
    if([child kind] == CXMLTextKind) {            
    return [[[element children] objectAtIndex:0] stringValue];
    }
}   
NSMutableDictionary* d = [NSMutableDictionary dictionary];
for(CXMLNode* child in [element children]) {
id v = [Soap deserialize:child];
if(v == nil) { v = [NSNull null]; }
//[d setObject:v forKey:[child name]]; //seems to be duped (maybe my bad)
    //Extended by iDev on StackOverflow
    //http://stackoverflow.com/questions/10235496/sudzc-deserializeasdictionary-over-written-dictionary/10358458#10358458
    NSString* key = [child name]; 
    id check = [d objectForKey:key]; 
    if( check != nil ) {             
        NSInteger next = 1;             
        key = [NSString stringWithFormat:@"%@%04d", [child name], next];
        check = [d objectForKey:key]; 
        while( check != nil ) {                 
            next++; 
            key = [NSString stringWithFormat:@"%@%04d", [child name], next]; 
            check = [d objectForKey:key]; 
        } 
        [d setObject:v forKey:key]; 
    } 
    [d setObject:v forKey:[child name]]; 
    //End Extension
}
return d;

}

Answer 3

我发现你还必须放一个else块：

if( check != nil ) {             
    NSInteger next = 1;             
    key = [NSString stringWithFormat:@"%@%04d", [child name], next];
    check = [d objectForKey:key]; 
    while( check != nil ) {                 
        next++; 
        key = [NSString stringWithFormat:@"%@%04d", [child name], next]; 
        check = [d objectForKey:key]; 
    } 
    [d setObject:v forKey:key]; 
} else {
    [d setObject:v forKey:[child name]];
}
//End Extension

否则，"d"中的元素将被覆盖，因为 setObject 被调用了两次。

Answer 4

我不确定您如何应用修复程序，您是在反序列化为字典中替换整个代码还是附加到代码末尾？

请参阅有一个 for 循环，其中代码行

  [d setObject:v forKey:[child name]];

找到了，所以我猜你只是扩展了它，而不是关闭 for 循环，而只是在这里扩展它，对吗？

Answer 5

我在上面的代码中遇到了问题 - 它每次都会覆盖第一个条目 - 即我会得到一个包含 4 个项目的列表，第一个和第四个项目将被复制。

经过大量疲惫的逐步通过代码（不喜欢递归代码），我发现了我认为的问题所在;

我的代码如下：

    if( check != nil ) {
        NSInteger next = 1;
        key = [NSString stringWithFormat:@"%@%04d", [child name], next];
        check = [d objectForKey:key];
        while( check != nil ) {
            next++;
            key = [NSString stringWithFormat:@"%@%04d", [child name], next];
            check = [d objectForKey:key];
        }
        [d setObject:v forKey:key];  
    }
    else
    {
          [d setObject:v forKey:[child name]];
    }