如何绑定和取消绑定事件jquery:旋转木马脚本修改

Question

我有一个jQuery旋转木马脚本，我想稍微修改一下它的行为。以下是jsfiddle中的脚本和测试用例：http://jsfiddle.net/A4vHf/1/。下面是JS代码。

(function($) {
    $.fn.easyPaginate = function(options){
        var defaults = {                
            step: 4,
            delay: 100,
            numeric: true,
            nextprev: true,
            auto:false,
            pause:4000,
            clickstop:true,
            controls: 'pagination',
            current: 'current' 
        }; 
        var options = $.extend(defaults, options); 
        var step = options.step;
        var lower, upper;
        var children = $(this).children();
        var count = children.length;
        var obj, next, prev;        
        var page = 1;
        var timeout;
        var clicked = false;
        function show(){
            clearTimeout(timeout);
            lower = ((page-1) * step);
            upper = lower+step;
            $(children).each(function(i){
                var child = $(this);
                child.hide();
                if(i>=lower && i<upper){ setTimeout(function(){ child.fadeIn('fast') }, ( i-( Math.floor(i/step) * step) )*options.delay ); }
                if(options.nextprev){
                    if(upper >= count) { next.fadeOut('fast'); } else { next.fadeIn('fast'); };
                    if(lower >= 1) { prev.fadeIn('fast'); } else { prev.fadeOut('fast'); };
                };
            }); 
            $('li','#'+ options.controls).removeClass(options.current);
            $('li[data-index="'+page+'"]','#'+ options.controls).addClass(options.current);
            if(options.auto){
                if(options.clickstop && clicked){}else{ timeout = setTimeout(auto,options.pause); };
            };
        };
        function auto(){
            if(upper <= count){ page++; show(); }           
        };
        this.each(function(){ 
            obj = this;
            if(count>step){
                var pages = Math.floor(count/step);
                if((count/step) > pages) pages++;
                var ol = $('<ol id="'+ options.controls +'"></ol>').insertAfter(obj);
                if(options.nextprev){
                    prev = $('<li class="prev">Previous</li>')
                        .hide()
                        .appendTo(ol)
                        .click(function(){
                            clicked = true;
                            page--;
                            show();
                        });
                };
                if(options.numeric){
                    for(var i=1;i<=pages;i++){
                    $('<li data-index="'+ i +'">'+ i +'</li>')
                        .appendTo(ol)
                        .click(function(){  
                            clicked = true;
                            page = $(this).attr('data-index');
                            show();
                        });                 
                    };              
                };
                if(options.nextprev){
                    next = $('<li class="next">Next</li>')
                        .hide()
                        .appendTo(ol)
                        .click(function(){
                            clicked = true;         
                            page++;
                            show();
                        });
                };
                show();
            };
        }); 
    };  
})(jQuery);

我的目标是使class="prev"和class="next"按钮始终可见。我从代码中删除了hide();方法，但我也需要删除点击事件处理程序，因为否则，即使在最后一页或第一页，我仍然可以点击按钮——这就是问题所在。我必须绑定和取消绑定点击事件，但不知道如何正确执行。这是我的修改版本：

(function($) {
$.fn.easyPaginate = function(options){
    var defaults = {                
        step: 4,
        delay: 100,
        numeric: true,
        nextprev: true,
        auto:false,
        pause:4000,
        clickstop:true,
        controls: 'pagination',
        current: 'current' 
    }; 
    var options = $.extend(defaults, options); 
    var step = options.step;
    var lower, upper;
    var children = $(this).children();
    var count = children.length;
    var obj, next, prev;        
    var page = 1;
    var timeout;
    var clicked = false;
    function show(){
        clearTimeout(timeout);
        lower = ((page-1) * step);
        upper = lower+step;
        $(children).each(function(i){
            var child = $(this);
            child.hide();
            if(i>=lower && i<upper){ setTimeout(function(){ child.fadeIn('fast') }, ( i-( Math.floor(i/step) * step) )*options.delay ); }
            if(options.nextprev){
                if(upper >= count) { next.fadeOut('fast'); } else { next.fadeIn('fast'); };
                if(lower >= 1) { prev.fadeIn('fast'); } else { prev.fadeOut('fast'); };
            };
        }); 
        $('li','#'+ options.controls).removeClass(options.current);
        $('li[data-index="'+page+'"]','#'+ options.controls).addClass(options.current);
        if(options.auto){
            if(options.clickstop && clicked){}else{ timeout = setTimeout(auto,options.pause); };
        };
    };
    function auto(){
        if(upper <= count){ page++; show(); }           
    };
    this.each(function(){ 
        obj = this;
        if(count>step){
            var pages = Math.floor(count/step);
            if((count/step) > pages) pages++;
            var ol = $('<ol id="'+ options.controls +'"></ol>').insertAfter(obj);
            if(options.nextprev){
                prev = $('<li class="prev">Previous</li>')
                    .appendTo(ol)
                    .bind('click', function() {
                        clicked = true;
                        page--;
                        show();
                    });
            };
            if(options.numeric){
                for(var i=1;i<=pages;i++){
                $('<li data-index="'+ i +'">'+ i +'</li>')
                    .appendTo(ol)
                    .click(function(){  
                        clicked = true;
                        page = $(this).attr('data-index');
                        show();
                    });                 
                };              
            };
            if(options.nextprev){
                next = $('<li class="next">Next</li>')
                    .appendTo(ol)
                    .bind('click', function() {
                        clicked = true;         
                        page++;
                        show();
                    });
            };
            show();
        };
    }); 
};  
})(jQuery);

Answer 1

如果用户已经到达页面的边界，那么在事件处理程序内部进行检查呢？

        if(options.nextprev){
            prev = $('<li class="prev">Previous</li>')
                .appendTo(ol)
                .bind('click', function() {
                    //check to see if there are any more pages in the negative direction
                    if (page > 0) {
                        clicked = true;
                        page--;
                        show();
                    }
                });
        }
        if(options.nextprev){
            next = $('<li class="next">Next</li>')
                .appendTo(ol)
                .bind('click', function() {
                    //check to see if there are any pages in the positive direction
                    if ((page + 1) < count) {
                        clicked = true;         
                        page++;
                        show();
                    }
                });
        }

更新

如果您希望上一个和下一个按钮永远不会消失，那么您需要删除show()函数中用于淡入和淡出元素的代码。这段代码是这样的：

        if(options.nextprev){
            if(upper >= count) { next.fadeOut('fast'); } else { next.fadeIn('fast'); };
            if(lower >= 1) { prev.fadeIn('fast'); } else { prev.fadeOut('fast'); };
        };

一个简单的修复方法就是评论这一部分，这里有一个演示：http://jsfiddle.net/A4vHf/18/