如何重新启动C++命令提示符应用程序

Question

我正在创建一个没有C++命令提示符的游戏。

这个游戏叫做PIG。你正在与电脑比赛，你的目标是通过掷骰子达到100游戏分数。如果你掷1分，你的回合结束，你的分数不会增加任何东西。如果你掷了任何其他数字，它会被添加到你的"转弯分数"中。滚动后，您可以选择再次滚动或"保持"。Holding将你的"回合得分"添加到你的"游戏得分"中，并将回合传给下一个玩家。

一切都按照我想要的方式进行，但现在我正在尝试创建一个playagain（）函数，该函数将在游戏结束时询问用户是否希望再次玩。如果他们这样做了，应用程序就会重新启动，所有变量都为零。如果没有，程序将退出。

以下是我的问题：

if(comp_score == 100){
    char ans;
    cout << "Your opponent has reached a score of 100 and has won! Would you like to play again? [y/n] ";
    cin >> ans;
    if(ans == 'y'){
        /*restarts application and zero's all variables*/
        playagain();
    } else if(ans == 'n'){ exit(); }}
    if(play_score == 100){
    char ans;
    cout << "You have reached a score of 100 and have won! Would you like to play again? [y/n] ";
    cin >> ans;
    if(ans == 'y'){
        /*restarts application and zero's all variables*/
        playagain();
    } else if(ans == 'n'){ exit(); }
}

TIA！

Answer 1

IMO实现这一点的最简单方法是使用while循环：

bool keep_playing = TRUE;
while (keep_playing)
  {
  keep_playing = FALSE;
  /* zero out variables */
  /* rest of code to play the game */
  if(comp_score == 100){
      char ans;
      cout << "Your opponent has reached a score of 100 and has won! Would you like to play again? [y/n] ";
      cin >> ans;
      if(ans == 'y'){
          keep_playing = TRUE;
      } else if(ans == 'n')
      { keep_playing = FALSE; }}
  if(play_score == 100){
    char ans;
    cout << "You have reached a score of 100 and have won! Would you like to play again? [y/n] ";
    cin >> ans;
    if(ans == 'y'){
      keep_playing = TRUE;
    } else if(ans == 'n')
    { keep_playing = FALSE; }}
  }  -- while (keep_playing)...

分享并享受。

Answer 2

如果您使用Windows，请记住。您可以使用ShellExecute打开一个新的游戏窗口，并给出一个返回代码0来关闭旧的窗口。就像这样。

#include <windows.h>   // >>>>>>  JACOBTECH EDIT.
if(comp_score == 100){
char ans;
cout << "Your opponent has reached a score of 100 and has won! Would you like to play again? [y/n] ";
cin >> ans;
if(ans == 'y'){
    /*restarts application and zero's all variables*/
    playagain();
} else if(ans == 'n'){ exit(); }}
if(play_score == 100){
char ans;
cout << "You have reached a score of 100 and have won! Would you like to play again? [y/n] ";
cin >> ans;
if(ans == 'y'){
    ShellExecuteA(NULL, "open", "C:/GameDirectory/Game.exe", NULL, NULL, SW_NORMAL);   //>>>>>>  JACOBTECH EDIT.
    return 0;  //>>>>>>  JACOBTECH EDIT.
} else if(ans == 'n'){ exit(); }

干杯！