为什么我会收到带有此代码的"NotSupportedException"？

Question

我试图用此代码从手持设备（紧凑型框架）调用Web API方法：

// "fullFilePath" is a value such as "Program FilesBlaabc.xml"
// "uri" is something like "http://localhost:28642/api/ControllerName/PostArgsAndXMLFile?serialNum=8675309&siteNum=42"
SendXMLFile(fullFilePath, uri, 500);
. . .
public static string SendXMLFile(string xmlFilepath, string uri, int timeout) 
{
    uri = uri.Replace('\', '/');
    if (!uri.StartsWith("/"))
    {
        uri = "/" + uri;
    }
    HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri);
    request.KeepAlive = false;
    request.ProtocolVersion = HttpVersion.Version10;
    request.Method = "POST";
    StringBuilder sb = new StringBuilder();
    using (StreamReader sr = new StreamReader(xmlFilepath))
    {
        String line;
        while ((line = sr.ReadLine()) != null)
        {
            sb.AppendLine(line);
        }
        byte[] postBytes = Encoding.UTF8.GetBytes(sb.ToString());
        if (timeout < 0)
        {
            request.ReadWriteTimeout = timeout;
            request.Timeout = timeout;
        }
        request.ContentLength = postBytes.Length;
        request.KeepAlive = false;
        request.ContentType = "application/x-www-form-urlencoded"; // not "text/xml" correct?
        try
        {
            Stream requestStream = request.GetRequestStream();
            requestStream.Write(postBytes, 0, postBytes.Length);
            requestStream.Close();
            using (var response = (HttpWebResponse)request.GetResponse())
            {
                return response.ToString();
            }
        }
        catch (Exception ex)
        {
            MessageBox.Show(ex.Message);
            request.Abort();
            return string.Empty;
        }
    }
}

sendxmlfile（）中的某个地方，它在" notsupportedexception >"中失败它逐步跨越它；我可以在整个（MessageBox.Show（））中撒上一堆调试语句，但我不想这样做。

服务器代码甚至从未达到我在" xdocument doc ="以下行上放置的断点：

[Route("api/ControllerName/PostArgsAndXMLFile")]
public void PostArgsAndFile([FromBody] string stringifiedXML, string serialNum, string siteNum)
{
    XDocument doc = XDocument.Parse(stringifiedXML); 

由于某种原因，紧凑型框架无法调用（休息）Web API方法？显然，客户端（手持/紧凑型框架）编译和运行，它只是拒绝实际遵循所有这些的运行时现实。

我的代码是否需要进行较小的更改才能适应它，还是需要完全不同的钉子？

Answer 1

Web API无法处理您的身体内容。您将其声明为application/x-form-urlencoded，但实际上是XML格式的，您的方法签名期望它是XMDATACNACTRACTENT序列化string。

而不是使用参数stringifiedXML，而只需阅读方法内的正文。

[Route("api/ControllerName/PostArgsAndXMLFile")]
public async void PostArgsAndFile(string serialNum, string siteNum)
{
    XDocument doc = XDocument.Parse(await Request.Content.ReadAsStringAsync()); 
}

或事件更好，直接使用流。

[Route("api/ControllerName/PostArgsAndXMLFile")]
public async void PostArgsAndFile(string serialNum, string siteNum)
{
    XDocument doc = XDocument.Load(await Request.Content.ReadAsStreamAsync()); 
}

这样，您可以将ContentType放在客户端回到application/xml上。

Answer 2

使用服务器端上的darrel的代码（我正在使用第二个，流），这在客户端上起作用：

public static string SendXMLFile(string xmlFilepath, string uri, int timeout)
{
    HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri);
    request.KeepAlive = false;
    request.ProtocolVersion = HttpVersion.Version10;
    request.ContentType = "application/xml";
    request.Method = "POST";
    StringBuilder sb = new StringBuilder();
    using (StreamReader sr = new StreamReader(xmlFilepath))
    {
        String line;
        while ((line = sr.ReadLine()) != null)
        {
            sb.AppendLine(line);
        }
        byte[] postBytes = Encoding.UTF8.GetBytes(sb.ToString());
        if (timeout < 0)
        {
            request.ReadWriteTimeout = timeout;
            request.Timeout = timeout;
        }
        request.ContentLength = postBytes.Length;
        request.KeepAlive = false;
        request.ContentType = "application/x-www-form-urlencoded";
        try
        {
            Stream requestStream = request.GetRequestStream();
            requestStream.Write(postBytes, 0, postBytes.Length);
            requestStream.Close();
            using (var response = (HttpWebResponse)request.GetResponse())
            {
                return response.ToString();
            }
        }
        catch (Exception ex)
        {
            MessageBox.Show(ex.Message);
            request.Abort();
            return string.Empty;
        }
    }
}

可以像这样称呼：

private void buttonNose_Click(object sender, EventArgs e)
{
    String fullFilePath = @"C:McMurtryLonesomeDove.XML";
    String uri = @"http://localhost:21608/api/inventory/sendxml/ff/gg/42";
    SendXMLFile(fullFilePath, uri, 500);
}