离子Instagram插件"Cannot read property 'slice' of undefined"

Question

我正在使用Ionic，当我试图通过ngCordova与Instagram插件分享图片时，这个错误发生在android上。我在网上看到一些像我这样的问题，但没有找到任何解决方案，所以也许有人可以帮助我。

10-14 20:29:51.202 4552-4552/? I/chromium: [INFO:CONSOLE(26794)] "TypeError: Cannot read property 'slice' of undefined
                                           at Object.Plugin.share (file:///android_asset/www/plugins/cordova-instagram-plugin/www/CDVInstagramPlugin.js:93:18)
                                           at Object.share (file:///android_asset/www/scripts/libs/ng-cordova.js:4805:17)
                                           at file:///android_asset/www/scripts/controllers/homeCtrl.js:206:31
                                           at file:///android_asset/www/lib/ionic/js/ionic.bundle.js:56230:19
                                           at Object.ionic.Platform.ready (file:///android_asset/www/lib/ionic/js/ionic.bundle.js:2140:9)
                                           at Object.self.ready (file:///android_asset/www/lib/ionic/js/ionic.bundle.js:56223:26)
                                           at home.shareInstagram (file:///android_asset/www/scripts/controllers/homeCtrl.js:205:26)
                                           at Object.$ionicPopup.show.buttons.onTap (file:///android_asset/www/scripts/controllers/homeCtrl.js:170:105)
                                           at Scope.extend.$buttonTapped (file:///android_asset/www/lib/ionic/js/ionic.bundle.js:56771:45)
                                           at fn (eval at <anonymous> (file:///android_asset/www/lib/ionic/js/ionic.bundle.js:27638:15), <anonymous>:4:386)", source: file:///android_asset/www/lib/ionic/js/ionic.bundle.js (26794)

Answer 1

好吧，也许对某些人有帮助。在描述的cordova instagram插件有写，我应该传递两个参数像这样

share(imageData, imageCaption)

，但这是一个错误，因为它应该作为对象传递参数，而不是两个值:

 $cordovaInstagram.share({image: image.data, caption: image.caption}).then(function() {
          // Worked
          alert('instagram sharing worked');
        }, function(err) {
          // Didn't work
          alert('instagram error');
        });