Pthread条件信号与工作线程

Question

有人能帮我完成下面的代码吗。我认为我的线程工作人员没有看到信号。我希望看到STEQUESIZE 1打印出来，但它从未发生过。如有任何帮助，我们将不胜感激。

输出为：

线程已启动互斥锁完成

#include <stdlib.h>
#include <stdio.h>
#include <signal.h>
#include <unistd.h>
#include <string.h>
#include <getopt.h>
#include <pthread.h>
#include <errno.h>
//  GLOBALS
pthread_mutex_t mutexqueue;
pthread_cond_t condworker;
pthread_t *threadIDs;
int STEQUESIZE=0;
void* worker(void *arg) {
 fprintf(stdout,"Thread Startedn");
 fflush(stdout);
  while (1) {
  pthread_mutex_lock(&mutexqueue);
    fprintf(stdout,"mutex lockedn");  fflush(stdout);
    while(STEQUESIZE == 0);
     pthread_cond_wait(&condworker, &mutexqueue);
    fprintf(stdout,"STEQUESIZE  %dn",STEQUESIZE);
    fflush(stdout);
    STEQUESIZE--;
  pthread_mutex_unlock(&mutexqueue);
  }
}
int main(int argc, char **argv) {
  int nthreads = 1;
  STEQUESIZE=0;
  pthread_mutex_t mutexqueue = PTHREAD_MUTEX_INITIALIZER;
  pthread_cond_t condworker = PTHREAD_COND_INITIALIZER;
  threadIDs = (pthread_t *)malloc(sizeof(pthread_t)*nthreads);
  int j;
  for(j=0; j< nthreads;j++)
     pthread_create(&threadIDs[j], NULL, worker, NULL);
  sleep(2);
    pthread_mutex_lock(&mutexqueue);
      STEQUESIZE=1;
      pthread_cond_signal(&condworker);
    pthread_mutex_unlock(&mutexqueue);
  printf("donen");
  while(1);
  return 0;
}

Answer 1

感谢评论回答了我的问题。全局变量和局部变量的名称相同。

//  GLOBALS
pthread_mutex_t mutexqueue;
pthread_cond_t condworker;
pthread_t *threadIDs;
int STEQUESIZE=0;

然后

int main(int argc, char **argv) {
  int nthreads = 1;
  STEQUESIZE=0;
  pthread_mutex_t mutexqueue = PTHREAD_MUTEX_INITIALIZER;
  pthread_cond_t condworker = PTHREAD_COND_INITIALIZER;