ADT表示，应用程序在用于启动新活动的点击事件后不幸停止

Question

我的第一个活动代码如下

public class MainActivity extends Activity {
Button mainActLoginBtn, mainActCreateBtn;
EditText mainActUserEdt, mainActPswEdt;
TextView tv;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    mainActLoginBtn = (Button) findViewById(R.id.btn1);
    mainActCreateBtn = (Button) findViewById(R.id.btn2);
    mainActUserEdt = (EditText) findViewById(R.id.edt1);
    mainActPswEdt = (EditText) findViewById(R.id.edt2);
    tv = (TextView) findViewById(R.id.tview);
    mainActLoginBtn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View arg0) {
            String userString = mainActUserEdt.getText().toString();
            String pswString = mainActPswEdt.getText().toString();
            if (userString.contentEquals("Dev")
                    && pswString.contentEquals("1234")) {
                tv.setText("Welcome " + userString
                        + "Click Proceed to further process");
                Intent successAct = new Intent("com.example.a_m_s.INTRO");
                startActivityForResult(successAct, 0);
            }
        }
    });
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.main, menu);
    return true;
}

应用程序未成功运行显示第一个窗口，该窗口是输入登录凭据并单击登录按钮后的登录窗口，在Android Emulator中生成错误我不知道如果需要更多的参考代码，会有什么问题，请询问。

Answer 1

试试这个。。

Intent successAct = new Intent(MainActivity.this,INTRO.class);
                startActivity(successAct);

示例：

mainActLoginBtn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View arg0) {
            String userString = mainActUserEdt.getText().toString();
            String pswString = mainActPswEdt.getText().toString();
            if (userString.contentEquals("Dev")
                    && pswString.contentEquals("1234")) {
                tv.setText("Welcome " + userString
                        + "Click Proceed to further process");
                 Intent successAct = new Intent(MainActivity.this,INTRO.class);
                    startActivity(successAct);
            }
        }
    });

Answer 2

除了写startActivityForResult(successAct, 0);，还需要写startActivity(successAct);

mainActLoginBtn.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View arg0) {
        String userString = mainActUserEdt.getText().toString();
        String pswString = mainActPswEdt.getText().toString();
        if (userString.contentEquals("Dev")
                && pswString.contentEquals("1234")) {
            tv.setText("Welcome " + userString
                    + "Click Proceed to further process");
             Intent successAct = new Intent("com.example.a_m_s.INTRO");
                startActivity(successAct);
        }
    }
});