我正在努力将超链接添加到我生成的 excel 文件的另一个列表中。我是这样试过的:
ws.Cells[1, 1].Formula="HYPERLINK("[#]'sheetName'!R4C1";"linktext")"
ws.Cells[1, 1].Formula="HYPERLINK("#'sheetName'!R4C1";"linktext")"
ws.Cells[1, 1].FormulaR1C1="HYPERLINK("[#]'sheetName'!R4C1";"linktext")"
ws.Cells[1, 1].FormulaR1C1="HYPERLINK("#'sheetName'!R4C1";"linktext")"
在excel 365(完整的离线应用程序)中打开生成的excel文件后,我只是收到消息,指出文件中存在错误,并且我使用此超链接公式的所有单元格都是空的。
错误消息是:
we found a problem with some content in FILENAME do you want us to try to recover as much as we can
如何让它工作?
此外,当我手动将相同的公式放入单元格中时,它可以工作。
完整代码:
using OfficeOpenXml;
using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace ExcelHyperlinkTest
{
class Program
{
static void Main(string[] args)
{
MemoryStream excelStream = new MemoryStream();
ExcelPackage excelFile = new ExcelPackage(excelStream);
ExcelWorksheet wsSrc = excelFile.Workbook.Worksheets.Add("src");
ExcelWorksheet wsTgt = excelFile.Workbook.Worksheets.Add("tgt");
wsSrc.Cells[1, 1].Formula = string.Format("HYPERLINK("#'{0}'!R{1}C{2}";"{3}")", "tgt", 2, 5, "test"); //FormulaR1C1
excelFile.Save();
excelStream.Position = 0;
using (FileStream file = new FileStream("c:\linkTest.xlsx", FileMode.Create, System.IO.FileAccess.Write))
{
byte[] bytes = new byte[excelStream.Length];
excelStream.Read(bytes, 0, (int)excelStream.Length);
file.Write(bytes, 0, bytes.Length);
excelStream.Close();
}
}
}
}
这有效
wsSrc.Cells[1, 6].Value = "test3";
Uri url = new Uri("#'tgt'!B5", UriKind.Relative);
wsSrc.Cells[1, 6].Hyperlink = url;
如果工作表存在于同一个 excel 文件中,并且任何使用 EPPlus 库的文件,那么以下代码可能会对他们有所帮助:
int rowCount=<your specific row>
ws.Cells[rowCount, 6].Hyperlink = new ExcelHyperLink((char)39 + "Name of your sheet" +
(char)39 + "!A1(specific cell on that sheet)", "Link text");
这将链接到工作簿(工作簿路径)中工作表(工作表名称)中的 B5,相对于当前工作簿,并将链接格式化为超链接
using (ExcelRange rng = xlsheetSummary.Cells[1, 1])
{
var namedStyle = xlsheetSummary.Workbook.Styles.NamedStyles.FirstOrDefault(o=> o.Name == "HyperLink");
namedStyle.Style.Font.UnderLine = true;
rng.StyleName = namedStyle.Name;
rng.Value = ws.Name;
Uri link = new Uri($"{workbookPath}#'{sheetName}'!B5", UriKind.Relative);
namedStyle.Style.Font.Color.SetColor(Color.Blue);
rng.Hyperlink = link;
}