线程:如何在没有太多代码的情况下解决此问题

Question

主要目的是根据页数创建多个线程有什么方法可以让它比制造大量的if更容易吗？无法知道如何正确解决此问题。

import threading
from bs4 import BeautifulSoup
from os import system, name
import requests
import sqlite3
import time
from dhooks import Webhook, Embed
import pprint
from threading import Thread

def page_check(URL):
page = requests.get(URL)
soup = BeautifulSoup(page.text, 'html.parser')
products = soup.find('div', attrs={'class': 'category-products'}).findAll('ul', attrs={'class': 'products-grid'})
print(products)
def page_start(count):
count = str(count)
URL = 'html/page/' + count + '/ke'
threading.Thread(target=page_check(URL)).start()
def number_of_pages():
URL = 'html/page/'
sites = requests.get(URL)
soup = BeautifulSoup(sites.text, 'html.parser')
number = soup.find('p', attrs={'class': 'amount mobilehidden'}).text
number = number.split()
number = int(number[5])
pages1 = number / 48
pages2 = int(number / 48)
if (pages1 / pages2) > 1:
pages = pages2 + 1
elif (pages1 / pages2) == 1:
pages = pages2
return pages
def main():
pages = number_of_pages()
if pages == 1:
threading.Thread(target=page_check('htmlpage/p/1/limit/48.html')).start()
if pages == 2:
threading.Thread(target=page_check('htmlpage/p/1/limit/48.html')).start()
threading.Thread(target=page_check('htmlpage/p/2/limit/48.html')).start()
if pages == 3:
threading.Thread(target=page_check('htmlpage/p/1/limit/48.html')).start()
threading.Thread(target=page_check('htmlpage/p/2/limit/48.html')).start()
threading.Thread(target=page_check('htmlpage/p/3/limit/48.html')).start()
main()

Answer 1

您正在寻找一个for循环和range方法。

num_pages = 3
for i in range(num_pages):
page_start(i)
# 0
# 1
# 2

range((将提供从0到(但不包括(目标数字的可迭代值。您也可以提供一个起始值，例如，范围(1，4(将计数1，2，3。有关更多选项，请参阅文档。

编辑：这只是讨论了如何避免多个if语句。要启动多个线程，请使用Python并发模块：https://docs.python.org/3/library/concurrent.futures.html#threadpoolexecutor

Answer 2

将此代码添加到main中，我将执行它。感谢大家

code = ''
while pages > 0:
count = str(count)
URL = 'htmlpage' + count + '/limit/48.html'
code = code + 'threading.Thread(target=page_check(' + "'" +  URL + "'" + ')).start()' + 'n'
pages = pages - 1
count = int(count)
count = count + 1