在android中，你如何搜索互联网并在活动中返回结果

Question

我希望用户将他们的搜索查询输入到搜索小部件中，然后将搜索结果显示给他们，然后当他们点击他们想要的url时，我需要能够保存该url以便在我的应用程序的其他部分使用。

这是可能的吗?如果不可能，有哪些限制阻止了这一点?

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编辑-我想我会添加代码为我的活动，有webview。

public class State extends Activity {
     @Override
     public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        final boolean customTitleSupport = requestWindowFeature(Window.FEATURE_CUSTOM_TITLE);
        setContentView(R.layout.state);
        if( customTitleSupport ){
            getWindow().setFeatureInt(Window.FEATURE_CUSTOM_TITLE, R.layout.title );
        }
        final TextView myTitleText = (TextView)findViewById(R.id.my_title);
        if( myTitleText != null ){
            myTitleText.setText(R.string.app_name);
        }
        WebView stateBrowser = (WebView)findViewById(R.id.state_search);
        stateBrowser.loadUrl("http://www.google.com/");
    }
}

Answer 1

你需要使用WebViewClient

public class WebViewTestActivity extends Activity implements
        View.OnClickListener {
    /** Called when the activity is first created. */
    Button btn = null;
    WebView myWebView =null;
    EditText et =null;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        btn = (Button) findViewById(R.id.button1);
        btn.setOnClickListener(this);
        et = (EditText) findViewById(R.id.editText1);
        myWebView = (WebView) findViewById(R.id.webview);
// WebViewClient in use.
        myWebView.setWebViewClient(new WebViewClient(){
            @Override
            public void onPageFinished(WebView view, String url) {
                super.onPageFinished(view, url);
                et.setText(url);
            }
        });
    }
    @Override
    public void onClick(View source) {
        if (btn.getText().equals("Go!")) {
            myWebView.loadUrl(et.getText().toString());
        }
    }
}

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