Rails 3.1创建记录而不是更新



我的Rails(3.1)应用程序中有以下Nokogiri rake任务:

desc "Import incoming calls"
task :fetch_incomingcalls => :environment do
    # Logs into manage.dial9.co.uk and retrieved list of incoming calls.
    require 'rubygems'
    require 'mechanize'
    require 'logger'
    # Create a new mechanize object
    agent = Mechanize.new
    # Load the dial9 website
    page = agent.get("https://manage.dial9.co.uk/login")
    # Select the first form
    form = agent.page.forms.first
    form.username = 'username
    form.password = 'password'
    # Submit the form
    page = form.submit form.buttons.first
    # Click on link called Call Logs
    page = agent.page.link_with(:text => "Call Logs").click
    # Click on link called Incoming Calls
    page = agent.page.link_with(:text => "Incoming Calls").click
    # Output results to file
    # output = File.open("output.html", "w") { |file|  file << page.search("tbody td").text.strip }
    # Add each row to a new call record
    page = agent.page.search("table tbody tr").each do |row|
      next if (!row.at('td'))
      time, source, destination, duration = row.search('td').map{ |td| td.text.strip }
      Call.create!(:time => time, :source => source, :destination => destination, :duration => duration)
    end
end

时间值是表中的第一行,每次调用都是唯一的(因为我们一次只能接收一个调用)。

我想做的是使用时间值作为我的呼叫日志的唯一标识符。

因此,当抓取屏幕时,它会"更新"现有的调用(这不会改变,但这是我唯一能想到的只导入新调用的方法)。

如果我将其设置为:

Call.find_all_by_time(nil).each do |call|

然后:

call.update_attribute(:time, time)

然后它将更新现有记录,但我希望它根据时间值导入数据库中尚未存在的记录。

感谢您的帮助!

你是这个意思吗?

# Add each row to a new call record
page = agent.page.search("table tbody tr").each do |row|
  next if (!row.at('td'))
  time, source, destination, duration = row.search('td').map{ |td| td.text.strip }
  call = Call.find_or_create_by_time(time)
  call.update_attributes({:time => time, :source => source, :destination => destination, :duration => duration})
end

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