我在获得一个简单的STI应该匹配器规范正确通过时遇到了问题。
这是它们之间的联系。
class User < ActiveRecord::Base
end
class Provider < ActiveRecord::Base
belongs_to :practice_manager, class_name: 'User', foreign_key: :user_id
end
class PracticeManager < User
has_many :providers
end
. .还有我的工厂…
FactoryGirl.define do
sequence(:email) { |n| "person#{n}@email.com" }
sequence(:password) { |p| "thepassword123" }
sequence(:password_confirmation) { |p| "thepassword123" }
factory :user do
email
password
password_confirmation
end
factory :practice_manager, parent: :user, class: 'PracticeManager' do
end
factory :provider_user, parent: :user, class: 'ProviderUser' do
end
factory :provider do
sequence(:first_name) { |n| "Sally#{n}" }
sequence(:last_name) { |n| "Harmon#{n}" }
sequence(:npi) { |n| n.to_s.rjust(10, '0')}
sequence(:sf_contact_ident) { |s| s.to_s.rjust(15, '0') }
practice_manager
end
end
. .还有我要通过的考试
require 'rails_helper'
RSpec.describe PracticeManager, type: :model do
describe "Relationships" do
it { should have_many(:providers).class_name('User').with_foreign_key(:user_id) }
end
end
我发现的一件事是,如果我将class_name: 'User', foreign_key: :user_id
添加到关联的has_many
侧,我可以通过测试,但我担心这是一个假阳性。这似乎不对。
我想你把你的联想搞混了。
要在您的PracticeManager模型中测试has_many
,您只需:
RSpec.describe PracticeManager, type: :model do
describe "Relationships" do
it { should have_many(:providers) }
end
end
如果你想测试你的Provider模型,那么你需要额外的选项:
RSpec.describe Provider, type: :model do
it { should belong_to(:practice_manager).class_name('User').with_foreign_key(:user_id) }
end