我需要在另一个公共秘书中执行周期性序列，并获取每个人的数据和每个状态，我对代码的问题是，它不会迭代数据我正在交付。当我拥有空字段时，我需要第二个for-EATH，然后可以使用Word Content Controls
XML文件
<?xml version="1.0"?>
<emailList>
<person>
<name>name 1</name>
<email>g@gmail.com</email>
<status>
<active>1</active>
<active>2</active>
<active>3</active>
</status>
</person>
<person>
<name>name 2</name>
<email>n@hotmail.com</email>
<status>
<active>4</active>
<active>5</active>
</status>
</person>
</emailList>
XSL文件
<xsl:stylesheet version="1.0">
<html xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xsl:version="1.0">
<head>
<title>Email Listing</title>
</head>
<body>
<table>
<tr>
<th>Name</th>
<th>E-mail Address</th>
<th>Status</th>
</tr>
<xsl:for-each select="emailList/person">
<tr>
<td><xsl:value-of select="name"/></td>
<td><xsl:value-of select="email"/></td>
<td>
<xsl:for-each select="emailList/person/status">
<xsl:value-of select="active"/>
</xsl:for-each>
</td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
您的内部xsl:for-each将相对于外部选择person。
尝试将其更改为...
<xsl:for-each select="status/active">
<xsl:value-of select="."/>
</xsl:for-each>
其中.选择当前节点。
如果您想通过逗号分开值，则可以做到....
<xsl:for-each select="status/active">
<xsl:if test="position() > 1">,</xsl:if>
<xsl:value-of select="."/>
</xsl:for-each>
更好的是，升级到XSLT 2.0，然后完全取消此xsl:for-each ..
<td>
<xsl:value-of select="status/active" separator="," />
</td>
<xsl:template match="/">
<html>
<head>
<title>Email Listing</title>
</head>
<body>
<table>
<tr>
<th>Name</th>
<th>E-mail Address</th>
<th>Status</th>
</tr>
<xsl:for-each select="emailList/person">
<tr>
<td><xsl:value-of select="name"/></td>
<td><xsl:value-of select="email"/></td>
<td>
<xsl:for-each select="status">
<xsl:value-of select="active"/>
</xsl:for-each>
</td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>