Pyside2 |找出按下哪个Qkey序列2

Question

我在这里有一个关于Qkey序列的问题。它有效，但是当我将其应用于我的代码时，当按钮点击事件在QkeySequence Line之前进行时，Qkey序列出现后似乎是错误的。

注意：GUI仅由两个按钮组成：self.btndsr和self.btnother。

在上一个问题中从eyllanesc的答案中获取，我的代码如下：

class MainWindow(QtWidgets.QMainWindow, test_mainWindow.Ui_MainWindow):
    def __init__(self, parent=None):
        super(MainWindow, self).__init__(parent)
        self.setupUi(self)
        self.signals()
    @QtCore.Slot()
    def test_func(self):
        shorcut = self.sender()
        sequence = shorcut.key()
        print(sequence.toString())
    def btn_clicked(self):
        QtWidgets.QShortcut(QtGui.QKeySequence("3"), self, activated=self.test_func)
        print('Shortcut 3 now works!')  # But it doesn't
    def signals(self):
        QtWidgets.QShortcut(QtGui.QKeySequence("1"), self, activated=self.test_func)
        QtWidgets.QShortcut(QtGui.QKeySequence("2"), self, activated=self.test_func)
        QtCore.QObject.connect(self.btnDSR, QtCore.SIGNAL('clicked()'), self.btn_clicked)
        QtCore.QObject.connect(self.btnOther, QtCore.SIGNAL('clicked()'), self.close)

单击BTNDSR后仅键入1和2个作品，输入3不起作用。这意味着数字3不是在打印出来，而是单击时数字1和2。按3：

时返回此错误消息

sequence = shorcut.key()
AttributeError: 'NoneType' object has no attribute 'key'

如果它很重要，我还在此处附上我的基本代码：

from PySide2 import QtCore, QtGui, QtWidgets
class Ui_MainWindow(object):
    def setupUi(self, MainWindow):
        MainWindow.setObjectName("MainWindow")
        MainWindow.resize(440, 418)
        self.centralwidget = QtWidgets.QWidget(MainWindow)
        self.centralwidget.setObjectName("centralwidget")
        self.btnDSR = QtWidgets.QPushButton(self.centralwidget)
        self.btnDSR.setGeometry(QtCore.QRect(120, 110, 93, 28))
        self.btnDSR.setObjectName("btnDSR")
        self.btnOther = QtWidgets.QPushButton(self.centralwidget)
        self.btnOther.setGeometry(QtCore.QRect(150, 180, 141, 28))
        self.btnOther.setObjectName("btnOther")
        MainWindow.setCentralWidget(self.centralwidget)
        self.btnDSR.setText(QtWidgets.QApplication.translate("MainWindow", "DSR Button", None, -1))
        self.btnOther.setText(QtWidgets.QApplication.translate("MainWindow", "Other Button", None, -1))
        QtCore.QMetaObject.connectSlotsByName(MainWindow)

Answer 1

使用pyqt5（使某些兼容性更改）进行测试，因此我认为这是Pyside2错误。解决方法是使用lambda或functools.partial通过键。

1。lambda：

class MainWindow(QtWidgets.QMainWindow, Ui_MainWindow):
    def __init__(self, parent=None):
        super(MainWindow, self).__init__(parent)
        self.setupUi(self)
        self.signals()
    @QtCore.Slot(str)
    def test_func(self, key):
        print(key)
    def btn_clicked(self):
        QtWidgets.QShortcut(QtGui.QKeySequence("3"), self, activated=  lambda key="3": self.test_func(key))
        print('Shortcut 3 now works!')  # But it doesn't
    def signals(self):
        QtWidgets.QShortcut(QtGui.QKeySequence("1"), self, activated=  lambda key="1": self.test_func(key))
        QtWidgets.QShortcut(QtGui.QKeySequence("2"), self, activated=  lambda key="2": self.test_func(key))
        QtCore.QObject.connect(self.btnDSR, QtCore.SIGNAL('clicked()'), self.btn_clicked)
        QtCore.QObject.connect(self.btnOther, QtCore.SIGNAL('clicked()'), self.close)

2。functools.partial

class MainWindow(QtWidgets.QMainWindow, Ui_MainWindow):
    def __init__(self, parent=None):
        super(MainWindow, self).__init__(parent)
        self.setupUi(self)
        self.signals()
    @QtCore.Slot(str)
    def test_func(self, key):
        print(key)
    def btn_clicked(self):
        QtWidgets.QShortcut(QtGui.QKeySequence("3"), self, activated= partial(self.test_func, "3"))
        print('Shortcut 3 now works!')  # But it doesn't
    def signals(self):
        QtWidgets.QShortcut(QtGui.QKeySequence("1"), self, activated= partial(self.test_func, "1"))
        QtWidgets.QShortcut(QtGui.QKeySequence("2"), self, activated= partial(self.test_func, "2"))
        QtCore.QObject.connect(self.btnDSR, QtCore.SIGNAL('clicked()'), self.btn_clicked)
        QtCore.QObject.connect(self.btnOther, QtCore.SIGNAL('clicked()'), self.close)