在我的程序中，我想在英雄健康为0不是整个程序时退出功能.我可以做什么

Question

当用户输入food ='苹果'健康时，在我的循环中，它将持续到3次，我想在健康变为0 0r小于0时退出循环。<<
我如何解决退出循环之外的问题，但继续剩下的程序？

print("Let us play a game")
class Hero():
def __init__(self, heroName):
    self.heroName = heroName
    self.health = 100
def game(self, food):
    if food == 'Apple':
        print("Hero is dead")
        self.health = self.health - 100
    #something to do here I think
    elif food == 'Banana':
        self.health +=30
    elif food == 'Pear':
        self.health -= 40
    else:
        print("We are strict to our rules You just got 3 choices")
    x = input("Press <A> to continue")
   if x == 'a':
   name = input("Enter Your Name")
  print("Welcome!",name, " You can Play An Intersting Game")
  heroName = input(" What name do you want to give your hero")
  hero = Hero(heroName)
  print("Ok, Your Hero is ", hero.heroName)
  print("Now lets paly the game...nn You have three choices to food your 
  hero (i) Apple (ii) Banana (iii) Pearnn")
 i = 0
 while i < 3:
    food = input("What You want your hero to feed")
    hero.game(food)
    print("Life of",hero.heroName,"is",hero.health)
    i +=1

  sth = input("Press anykey and then hit <ENTER> to exit...")

Answer 1

当英雄的健康为 <= 0时，您应该break。添加

之类的东西

if hero.health <= 0:
    break

在循环中的合适位置。

Answer 2

类似的东西：

只需退出循环含义

while something:
    if self.health <= 0:
       break

退出功能并继续使用程序

while something:
    if self.health <= 0:
        break
call_hero()

Answer 3

print "Let us play a game"
class Hero():
     def __init__(self, heroName):
     self.heroName = heroName
     self.health = 100
def game(self, food):
    if food == 'Apple':
       print"Hero is dead"
       self.health = self.health - 100
   elif food == 'Banana':
      self.health +=30
  elif food == 'Pear':
     self.health -= 40
  else:
   print "We are strict to our rules You just got 3 choices"
x = raw_input("Press 'a' to continue")
if x == 'a':
    name = str(raw_input("Enter Your Name"))
    print "Welcome!",name, " You can Play An Intersting Game"
    heroName =str(raw_input(" What name do you want to give your hero"))
    hero = Hero(heroName)
    print "Ok, Your Hero is ", hero.heroName
    print "Now lets paly the game...nn You have three choices to food your 
    hero (i) Apple (ii) Banana (iii) Pearnn"
i = 0
else:
   print "entry not allowed"
   i=4
while i < 3:
     food=str(raw_input("What You want your hero to feed"))
     hero.game(food)
     if hero.health<1:
          i=i+4
     else:
          print "Life of",hero.heroName,"is",hero.health
          i +=1
sth = str(raw_input("Press anykey and then hit <ENTER> to exit..."))

您可以使用此代码来学习并使您的有趣游戏来解决问题。