多维数组值jquery

Question

需要一些帮助与一个脚本完全对数组，我正在做

    skill = [
        //[ID, "NAME", TMLEVEL, Learn, Mastery, Prerequisite, PrerequisiteLvl],
        //Schoolgirl, Fighter
        [0, "Steel Punch", 0, 0, null, null],
        [1, "Shockwave", 1, 1, 2, null],
        [2, "Bull's Eye", 10, 2, 2, null],
        [3, "Burning Rave", 20, 2, 2, null],
        [4, "Shockvibe", 20, 1, 2, null],
        [5, "Sense Breaker", 20, 1, 2, null],
        [6, "Luck Breaker", 20, 1, 2, null],
        [7, "Pumping Heart", 25, 3, 3, skill[3], 1],
        [8, "Armor Breaker", 30, 2, 2, skill[1], 10],
        [9, "Upper Smash", 40, 2, 2, skill[2], 10],
        [10, "Hyper Beat", 45, 4, 3, [skill[2],skill[3]], [10,10]],
        [11, "Tornado Bomb", 50, 3, 3, skill[8], 1]
    ];

我需要在数组内部，在某些点，再次调用数组把数组的值放进去，就像这里一样。理论上这工作得很好，没有任何错误，但是当我调用它里面的数组时，它说它是"未定义的"。

有谁知道我怎么能做到这一点，而不重写上面的一切吗?(因为我在+- 300代码行中使用这个)。

Answer 1

经过漫长的过程，我已经提出了一个解决方案，将取代所有先决条件，即使他们是几个层次的深度(例如，skill_3需要skill_2，需要skill_1…)。

这将要求你的skill变量被正确声明(在你的问题中，不是所有的技能都有7个变量)。

下面是这个变量的示例:

var skill = [
    //[ID, "NAME", TMLEVEL, Learn, Mastery, Prerequisite, PrerequisiteLvl],
    [0, "Steel Punch",  0,  0,  0,  null,   null],
    [1, "Shockwave",    1,  1,  2,  null,   null],
    [2, "Bull's Eye",   10, 2,  2,  7,      null],
    [3, "Burning Rave", 20, 2,  2,  null,   null],
    [4, "Shockvibe",    20, 1,  2,  null,   null],
    [5, "Sense Breaker",20, 1,  2,  null,   null],
    [6, "Luck Breaker", 20, 1,  2,  null,   null],
    [7, "Pumping Heart",25, 3,  3,  3,      1],
    [8, "Armor Breaker",30, 2,  2,  7,      10],
    [9, "Upper Smash",  40, 2,  2,  2,      10],
    [10,"Hyper Beat",   45, 4,  3,  [2,3],  [10,10]],
    [11,"Tornado Bomb", 50, 3,  3,  8,      1]
];

现在，我想到了一个函数setPrerequisites()，它将为一个技能递归地设置它的先决条件:

Array.prototype.setPrerequisites = function(){
    if (typeof this[5] === "number")
    {
        this[5]=skill[getPosOfSkill(this[5])];
        this[5].setPrerequisites();
    }
    else if (this[5] instanceof Array)
    {
        if (this[5].isSkill()) this[5].setPrerequisites();
        else
        {
            for(var i = 0; i < this[5].length; i++)
            {
                this[5][i] = skill[getPosOfSkill(this[5][i])];
                this[5][i].setPrerequisites();
            }
        }
    }
}

该函数使用isSkill()来判断一个数组是技能还是技能id数组:

Array.prototype.isSkill = function(){
    return this.length==7 && typeof this[1]==="string";
}

它还使用getPosOfSkill(id)来寻找正确的技能，以防您的技能在没有特定顺序列出，或者如果ID缺失:

function getPosOfSkill(id){
    for(var i=0; i<skill.length; i++) if (skill[i][0]==id) return i;
    return false;
}

你所要做的就是声明你的skill变量，然后填充它:

for (var i = 0; i < skill.length; i++) skill[i].setPrerequisites();
// if you want to see the results
console.log(skill);

这是一个jsFiddle Demo

Answer 2

您必须重新考虑这里的整个方法(建议)，或者首先将这些项设置为null，然后重新运行声明:

skill = [
    //[ID, "NAME", TMLEVEL, Learn, Mastery, Prerequisite, PrerequisiteLvl],
    //Schoolgirl, Fighter
    [0, "Steel Punch", 0, 0, null, null],
    [1, "Shockwave", 1, 1, 2, null],
    [2, "Bull's Eye", 10, 2, 2, null],
    [3, "Burning Rave", 20, 2, 2, null],
    [4, "Shockvibe", 20, 1, 2, null],
    [5, "Sense Breaker", 20, 1, 2, null],
    [6, "Luck Breaker", 20, 1, 2, null],
    [7, "Pumping Heart", 25, 3, 3, null, 1],
    [8, "Armor Breaker", 30, 2, 2, null, 10],
    [9, "Upper Smash", 40, 2, 2, null, 10],
    [10, "Hyper Beat", 45, 4, 3, null, null],
    [11, "Tornado Bomb", 50, 3, 3, null, 1]
];
skill = [
    //[ID, "NAME", TMLEVEL, Learn, Mastery, Prerequisite, PrerequisiteLvl],
    //Schoolgirl, Fighter
    [0, "Steel Punch", 0, 0, null, null],
    [1, "Shockwave", 1, 1, 2, null],
    [2, "Bull's Eye", 10, 2, 2, null],
    [3, "Burning Rave", 20, 2, 2, null],
    [4, "Shockvibe", 20, 1, 2, null],
    [5, "Sense Breaker", 20, 1, 2, null],
    [6, "Luck Breaker", 20, 1, 2, null],
    [7, "Pumping Heart", 25, 3, 3, skill[3], 1],
    [8, "Armor Breaker", 30, 2, 2, skill[1], 10],
    [9, "Upper Smash", 40, 2, 2, skill[2], 10],
    [10, "Hyper Beat", 45, 4, 3, [skill[2],skill[3]], [10,10]],
    [11, "Tornado Bomb", 50, 3, 3, skill[8], 1]
];

这样，你要访问的数组元素已经存在，现在你只是覆盖它们。

Answer 3

我想我找到了一个简单的方法，但仍然有问题，如果它被定义后，但因为我只调用之前定义的值，现在没有问题。

但如果有人知道什么更好的方法，请告诉我。

下面是我只使用数组所做的:

    var skill = [];
    skill[0] = [0, "Steel Punch", 0, 0, null, null];
    skill[1] = [1, "Shockwave", 1, 1, 2, null];
    skill[2] = [2, "Bull's Eye", 10, 2, 2, null];
    skill[3] = [3, "Burning Rave", 20, 2, 2, null];
    skill[4] = [4, "Shockvibe", 20, 1, 2, null];
    skill[5] = [5, "Sense Breaker", 20, 1, 2, null];
    skill[6] = [6, "Luck Breaker", 20, 1, 2, null];
    skill[7] = [7, "Pumping Heart", 25, 3, 3, skill[3], 1];
    skill[8] = [8, "Armor Breaker", 30, 2, 2, skill[1], 10];
    skill[9] = [9, "Upper Smash", 40, 2, 2, skill[2], 10];
    skill[10] = [10, "Hyper Beat", 45, 4, 3, [skill[2],skill[3]], [10,10]];
    skill[11] = [11, "Tornado Bomb", 50, 3, 3, skill[8], 1];

这样我定义它们，我仍然使用数组我想要的(1个晚上的睡眠让我想得更好:p)