我不确定为什么会出现这些错误,但最奇怪的是,我仍然能够运行程序并产生我想要的结果。
我得到的编译器错误是
IntelliSense:类型为"MyStruct*"的值不能分配给类型为"Mystuct_struct*"的实体
有4个这样的例子,但正如我在标题中所说,程序似乎仍然运行良好,并按照我的意愿显示bin文件。是的,我知道我的结构名称不好。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
typedef struct MyStruct_struct
{
char FlightNum[7];
char OriginAirportCode[5];
char DestAirportCode[5];
int timeStamp;
struct Mystruct_struct* next;
} MyStruct;
int main()
{
time_t time;
MyStruct * ptr;
MyStruct * head;
MyStruct * tail;
MyStruct * temp;
FILE * bin;
MyStruct myStruct;
bin = fopen("acars.bin", "rb");
ptr= (struct MyStruct_struct *) malloc (sizeof(MyStruct) );
fread(ptr,sizeof(MyStruct)-sizeof(MyStruct*),1,bin);
head = ptr; // make head point to that struct
tail = ptr; // make tail point to that struct
while (1)
{
ptr = (struct MyStruct_struct *) malloc(sizeof(MyStruct));
fread(ptr, sizeof(MyStruct) - sizeof(MyStruct*), 1, bin);
tail->next = ptr; // error here
tail = tail->next; //error here
if (feof(bin) != 0)
break;
}
tail->next = NULL;
ptr = head;
while (ptr->next != NULL)
{
printf("%s ", ptr->FlightNum);
printf("%s ", ptr->OriginAirportCode);
printf("%s ", ptr->DestAirportCode);
time = ptr->timeStamp;
printf("%s",ctime( &time));
ptr = ptr->next; // here
}
ptr = head;
while (ptr->next != NULL)
{
temp = ptr;
ptr = ptr->next; //error here
free(temp);
}
fclose(bin);
system("pause");
return 0;
}
您的结构定义中有一个拼写错误。下一个变量的类型是MyStuct_Struct。在MyStuct_Struct上检查拼写。它仍然有效,因为C显然不是类型安全的。指针就是指针,这样你就不会出现内存错误。