Python :P年龄导航器最大值抓取器 - 仅获取最后一个值的输出

Question

这是我创建的程序，用于从列表中的每个类别部分中提取最大页面值。我无法获取所有值，我只是获取列表中最后一个值的值。我需要进行哪些更改才能获得所有输出。

import bs4
from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup
#List for extended links to the base url
links = ['Link_1/','Link_2/','Link_3/']
#Function to find out the biggest number present in the page navigation
#section.Every element before 'Next→' is consist of the upper limit
def page_no():
bs = soup(page_html, "html.parser")
max_page = bs.find('a',{'class':'next page-numbers'}).findPrevious().text
print(max_page)
#url loop
for url in links:
my_urls ='http://example.com/category/{}/'.format(url)
# opening up connection,grabbing the page
uClient = uReq(my_urls)
page_html = uClient.read()
uClient.close()
page_no()

页面导航器示例：1 2 3 … 15 Next →

提前致谢

Answer 1

您需要将page_html放入函数中并缩进最后 4 行。此外，最好返回 max_page 值，以便您可以在函数旁边使用它。

def page_no(page_html): 
bs = soup(page_html, "html.parser")
max_page = bs.find('a',{'class':'next page-numbers'}).findPrevious().text
return max_page
#url loop 
for url in links: 
my_urls='http://example.com/category/{}/'.format(url) 
# opening up connection,grabbing the page 
uClient = uReq(my_urls) 
page_html = uClient.read()
uClient.close() 
max_page = page_no(page_html)
print(max_page)