原则查询生成器 - 嵌套查询

Question

如何将此查询转换为symfony 2 doctrine query builder？

SELECT
artist_id,
DATE,
balance,
TYPE
FROM TRANSACTION AS
t1
WHERE
DATE =(
SELECT
MAX(DATE)
FROM TRANSACTION
WHERE
artist_id = t1.artist_id AND
STATUS
IN(
'partial',
'pending',
'deducted',
'accepted'
) AND TYPE NOT LIKE 'payment'
)
GROUP BY
artist_id
ORDER BY
artist_id

我尝试了以下方法：

$qb = $this->getEntityManager()->createQueryBuilder()
->select('t.balance','a.id','t.date')
->from('TestMainBundle:Transaction','t')
->Join('t.artist','a')
->where("t.status in ('partial','pending','deducted','accepted')")
->andWhere("t.type NOT LIKE 'payment'")
->groupBy('a.id')
->orderBy('a.id');
return $qb->getQuery()->getResult();

但是我也坚持包括最大(日期(的条件。非常感谢对此的任何帮助。

Answer 1

您的教义查询将如下所示，

$qb1 = $this->getDoctrine()->getManager()->createQueryBuilder();        
$select = $qb1->select('MAX(date) AS max_data')
->from('YourBundle:Transaction', 's')
->where('s.artist_id = :ti_artist_id')
->andWhere('s.status IN (:statuses)')
->andWhere('s.type NOT LIKE :type')
->getQuery();
$qb2 = $this->getDoctrine()->getManager()->createQueryBuilder();
$result = $qb2->select('t.artist_id', 't.date', 't.balance', 't.type')
->from('YourBundle:Transaction', 't');
$result->where($qb2->expr()->eq('t.date', $select->getDQL()))
->setParameter('ti_artist_id', 't.id')
->setParameter('statuses', array('partial','pending','deducted','accepted'))
->setParameter('type', 'payment') //possibly '%payment%'
->orderBy('t.artist_id')
->getQuery()
->getResult();

干杯！！！