我如何编码(java library可以做到这一点(
a &到a%20%26
不使用String.replace()功能？
网址编码器 -> a+%26
URIUtil.encodePath -> a%20&
UrlEscapers.urlFragmentEscaper((.escape -> a%20&
org.apache.catalina.util.URLEncoder 就是答案
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