我已经能够在我的应用程序中获得Face/Touch ID的初级版本。但是,我想添加更好的回退和错误处理。
所以我一直在研究如何做到这一点。有这样的奇妙资源:
人脸识别评估过程工作不正常
然而,我在SwiftUI视图中找不到任何可用的东西。目前我的项目不会运行:
'unowned' may only be applied to class and class-bound protocol types, not 'AuthenticateView'
和
Value of type 'AuthenticateView' has no member 'present'
任何帮助都将不胜感激。非常感谢。
这是我在AuthenticateView.swift 中的代码
func Authenticate(completion: @escaping ((Bool) -> ())){
//Create a context
let authenticationContext = LAContext()
var error:NSError?
//Check if device have Biometric sensor
let isValidSensor : Bool = authenticationContext.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &error)
if isValidSensor {
//Device have BiometricSensor
//It Supports TouchID
authenticationContext.evaluatePolicy(
.deviceOwnerAuthenticationWithBiometrics,
localizedReason: "Touch / Face ID authentication",
reply: { [unowned self] (success, error) -> Void in
if(success) {
// Touch / Face ID recognized success here
completion(true)
} else {
//If not recognized then
if let error = error {
let strMessage = self.errorMessage(errorCode: error._code)
if strMessage != ""{
self.showAlertWithTitle(title: "Error", message: strMessage)
}
}
completion(false)
}
})
} else {
let strMessage = self.errorMessage(errorCode: (error?._code)!)
if strMessage != ""{
self.showAlertWithTitle(title: "Error", message: strMessage)
}
}
}
func errorMessage(errorCode:Int) -> String{
var strMessage = ""
switch errorCode {
case LAError.Code.authenticationFailed.rawValue:
strMessage = "Authentication Failed"
case LAError.Code.userCancel.rawValue:
strMessage = "User Cancel"
case LAError.Code.systemCancel.rawValue:
strMessage = "System Cancel"
case LAError.Code.passcodeNotSet.rawValue:
strMessage = "Please goto the Settings & Turn On Passcode"
case LAError.Code.touchIDNotAvailable.rawValue:
strMessage = "TouchI or FaceID DNot Available"
case LAError.Code.touchIDNotEnrolled.rawValue:
strMessage = "TouchID or FaceID Not Enrolled"
case LAError.Code.touchIDLockout.rawValue:
strMessage = "TouchID or FaceID Lockout Please goto the Settings & Turn On Passcode"
case LAError.Code.appCancel.rawValue:
strMessage = "App Cancel"
case LAError.Code.invalidContext.rawValue:
strMessage = "Invalid Context"
default:
strMessage = ""
}
return strMessage
}
func showAlertWithTitle( title:String, message:String ) {
let alert = UIAlertController(title: title, message: message, preferredStyle: .alert)
let actionOk = UIAlertAction(title: "OK", style: .default, handler: nil)
alert.addAction(actionOk)
self.present(alert, animated: true, completion: nil)
}
说明:
"已知"只能应用于类和类绑定协议类型,而不能应用于"AuthenticateView">
首先,您有AuthenticateView
,它是struct
。你不能做class
,因为整个苹果的SwiftUI理念都是关于结构的。因为Struct
是值类型,而不是引用类型,所以没有这样的指针。因此,您可能不会在struct AuthenticateView: View {}
中包含包含unowned self
和weak self
修饰符的代码部分
类型为"AuthenticateView"的值没有成员"present">
present
是UIViewController
的方法。在SwiftUI中,您无法访问它。警报将使用下一种样式显示:
struct ContentView: View {
@State private var show = false
var body: some View {
Button(action: { self.show = true }) { Text("Click") }
.alert(isPresented: $showingAlert) {
Alert(title: Text("Title"),
message: Text("Message"),
dismissButton: .default(Text("Close")))
}
}
}
解决方案:对于您的情况,我将为您的逻辑创建ObservableObject
的class
Handler子类,并使用@ObservedObject
、@Published
和@State
的功能。
理解概念的粗略示例:
import SwiftUI
struct ContentView: View {
@ObservedObject var handler = Handler()
var body: some View {
Button(action: { self.handler.toggleShowAlert() }) { Text("Click") }
.alert(isPresented: $handler.shouldShowAlert) {
Alert(title: Text(handler.someTitle),
message: Text(handler.someMessage),
dismissButton: .default(Text("Close")))
}
}
}
struct ContentView_Previews: PreviewProvider {
static var previews: some View {
ContentView()
}
}
class Handler: ObservableObject {
@Published var shouldShowAlert: Bool = false
@Published var someTitle = ""
@Published var someMessage = ""
func toggleShowAlert() {
shouldShowAlert.toggle()
someTitle = "ErrorTitle"
someMessage = "ErrorMessage"
}
}