PyGame排队音乐问题，不等待第一首歌

Question

我正在播放从我选择的音乐文件目录生成的列表中的ogg声音文件。由于某种原因，第一首歌被跳过，从第二首歌开始播放。出于某种原因，它偶尔会播放第一首歌的一瞬间，这让我相信我如何尝试从循环列表中排队播放歌曲存在问题，但我似乎无法修复它。

import pygame
import sys
import os
from pygame.locals import * 
surface = pygame.display.set_mode((640, 480))
musicDir = "/Users/user/Desktop/Dat Sound/Music/"
x = os.listdir(musicDir)
del(x[0]) # Deleting first element because it's DS Store file (Mac)
print x # The list is ['Bonfire.ogg', 'Voodoo Child.ogg']
n = ''
count = 1
pygame.mixer.init()
for i in range(len(x)):
    n = musicDir + str(x[i])
    print n  
    pygame.mixer.music.load(n)
    pygame.mixer.music.play()
    pygame.mixer.music.queue(musicDir + str(x[i]))
    # I'm queueing the next song in the list of songs from the folder + its location
    print pygame.mixer.music.get_busy() 
    # get_busy returns true for both files but only the second is playing
running = True
while running:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
          running = False

Answer 1

看起来你正在加载并播放一首歌，然后将其排队，但是在下一次循环迭代时加载并播放第二首歌，然后再次将其排队…

n = musicDir + str(x[i])
pygame.mixer.music.load(n) # so you load the song...
pygame.mixer.music.play()  # then you play it....
pygame.mixer.music.queue(musicDir + str(x[i])) # i hasn't changed, this is the same song 
                                               #  you just loaded and started playing

然后for循环到下一个迭代，你做完全相同的事情，但是用下一首歌。

试试这样写:

n = musicDir + str[0]   # let's load and play the first song
pygame.mixer.music.load(n)
pygame.mixer.music.play()
for song in x: 
    pygame.mixer.music.queue(musicDir + str(song)) # loop over and queue the rest