我在代码中使用拖放jquery ui。代码运行良好。但用户应该有一定的能力编辑保存后的数据。这意味着当用户再次打开页面时,我需要恢复拖放位置。我试着使用触发器,但我不能模仿"drop-ui"。我该怎么做?
$( ".draggable-children-username" ).draggable({
snap: ".draggable-in-box",
opacity: 0.7,
revert: 'invalid',
helper: "clone"
});
$(".draggable-in-box").droppable({
accept: $(".draggable-children-username"),
hoverClass: "dropHover",
drop: function (ev, ui) {
$(this).trigger("DopeEvent", ui);
}
});
$( ".draggable-in-box" ).bind("DopeEvent", function(event, ui ){
console.log(ui);
var me = ui.draggable.clone()
ui.draggable.draggable("disable")
me.appendTo(this)
.addClass("newClass");
me.draggable({
accept: ".draggable-in-box",
revert: function(valid) {
if(!valid) {
this.remove();
$(".dr-children-id-"+this.attr("data-id")).draggable("enable");
}
}
});
});
$( ".draggable-in-box" ).trigger("DopeEvent", $( ".dr-children-id-140" ));
当前错误:未捕获类型错误:ui.draggable.clone不是函数
http://jsfiddle.net/vjGY4/123/
一些修复。我认为你正在尝试做的工作示例:
http://jsfiddle.net/Twisty/vjGY4/125/
JQuery
$(".draggable-children-username").draggable({
snap: ".draggable-in-box",
opacity: 0.7,
revert: 'invalid',
helper: "clone"
});
$(".draggable-in-box").droppable({
accept: $(".draggable-children-username"),
hoverClass: "dropHover",
drop: function(ev, ui) {
$(this).trigger("DopeEvent", ui.draggable);
}
});
$(".draggable-in-box").bind("DopeEvent", function(event, ui) {
console.log(ui);
var me = $(ui).clone();
//ui.draggable.draggable("disable")
me.appendTo(this)
.addClass("newClass");
me.draggable({
accept: ".draggable-in-box",
revert: function(valid) {
if (!valid) {
this.remove();
$(".dr-children-id-" + this.attr("data-id")).draggable("enable");
}
}
});
});
$(".draggable-in-box").trigger("DopeEvent", $(".dr-children-id-140"));
- 不要假设
DopeEvent
中传递了一个可拖动对象或jquery对象。使用var me = $(ui).clone();
- 在您的
drop
中,您需要像这样传递元素:$(this).trigger("DopeEvent", ui.draggable);
希望能有所帮助。您可以通过检查正在通过的内容来改进您的活动。像if(typeof ui === "object"){}
这样的东西可以工作。