Django 用户配置文件查询

Question

几个小时以来，我一直在努力看看这段代码有什么问题。我正在处理的项目要求用户注册到站点（由 Django 注册插件负责。注册后，用户将能够将其公司（姓名，地址，电话等）作为列表添加到站点。所以公司有自己的模式。我正在使用 Django 配置文件在 Django 配置文件页面上显示用户信息和公司信息。配置文件也建立在Django Profiles插件之上。

url(r'^accounts/', include('registration.urls')),    
url(r'^admin_export/', include("admin_export.urls")),   
url(r'^profiles/edit', 'profiles.views.edit_profile'),
url(r'^profiles/create', 'profiles.views.create_profile'),
url(r'^profiles/', include('profiles.urls')),
url(r'^profiles/(?P<username>w+)/$', 'profiles.views.profile_detail',name='UserProfileView'),
url(r'^comments/', include('django.contrib.comments.urls'))

#models.py
class UserProfile(models.Model):
    user = models.ForeignKey(User,unique=True)
    #email = models.CharField(max_length=200, blank=True, null=True)
    # Other fields here
    #company = models.ForeignKey(Company,blank=True,null=True)    
    #office = models.CharField(max_length=200, blank=True, null=True)    
    def __unicode__(self):
        return self.user.username


class Company(models.Model):
    userprofile = models.ForeignKey(UserProfile, null=True, blank=True)
    comp_name = models.CharField(max_length=200,blank=True,null=True)
    comp_address = models.CharField(max_length=200,blank=True, null=True)
    comp_email = models.CharField(max_length=200,blank=True, null=True)
    comp_zip = models.IntegerField(blank=True, null=True)
    comp_phone = models.IntegerField(blank=True, null=True)
    comp_city = models.CharField(max_length=200,blank=True, null=True)
    #comp_state = models.USStateField(blank=True, null=True
    comp_state = models.CharField(blank=True, max_length=2)
    compwebsite = models.URLField(max_length=200, blank=True, null=True)
    twitterurl = models.URLField(max_length=200, blank=True, null=True)
    facebookurl = models.URLField(max_length=200, blank=True, null=True)
    def __unicode__(self):
        return self.comp_name
class ProfileForm(ModelForm):
    class Meta:
        model=UserProfile
        exclude=('user',)
#views.py
def UserProfileView(request, username):
    context_dict = {}
    usercompany =  get_object_or_404(Company, user=userprofile)
    context_dict = {'usercompany': usercompany}
    return render_to_response('profile_detail.html', context_dict, RequestContext(request))

Answer 1

userprofile在您的

views.py 中引用时实际上不可用，因此它应该引发NameError

如果我理解正确，实现这一目标的方法是：

#views.py
def UserProfileView(request):
    context_dict = {}
    usercompany =  get_object_or_404(Company, userprofile__user=request.user)
    context_dict = {'usercompany': usercompany}
    return render_to_response('profile_detail.html', context_dict, RequestContext(request))