C# 反序列化 Atom XML

Question

我想反序列化以下Atom XML：

<?xml version="1.0" encoding="UTF-8"?>
<feed xmlns="http://www.w3.org/2005/Atom" xmlns:openSearch="http://a9.com/-/spec/opensearchrss/1.0/" xmlns:tel="http://tel.search.ch/api/spec/result/1.0/" xml:lang="de">
<id>https://tel.search.ch/api/ed14c7f5e42390640730cb18523640d5</id>
<title type="text">tel.search.ch API Search Results</title>
<generator version="1.0" uri="https://tel.search.ch">tel.search.ch</generator>
<updated>2018-08-28T02:00:00Z</updated>
<link href="https://tel.search.ch/result.html?was=0418553553" rel="alternate" type="text/html" />
<link href="http://tel.search.ch/api/?was=0418553553" type="application/atom+xml" rel="self" />
<openSearch:totalResults>1</openSearch:totalResults>
<openSearch:startIndex>1</openSearch:startIndex>
<openSearch:itemsPerPage>10</openSearch:itemsPerPage>
<openSearch:Query role="request" searchTerms="1234567890 " startPage="1" />
<openSearch:Image height="1" width="1" type="image/gif">https://www.search.ch/audit/CP/tel/de/api</openSearch:Image>
<entry>
<id>urn:uuid:ef812a3ea1e8e6f0</id>
<updated>2018-08-28T02:00:00Z</updated>
<published>2018-08-28T02:00:00Z</published>
<title type="text">Power, Max</title>
<content type="text">Max Power, Firststreet 1 6000 Switzerland/SZ 123 456 78 90</content>
<tel:nopromo>*</tel:nopromo>
<author>
<name>tel.search.ch</name>
</author>
<link href="https://tel.search.ch/switzerland/maxPower" title="Details" rel="alternate" type="text/html" />
<link href="https://tel.search.ch/switzerland/maxPower" type="text/x-vcard" title="VCard Download" rel="alternate" />
<link href="https://tel.search.ch/edit/?id=ef812a3ea1e8e6f0" rel="edit" type="text/html" />
</entry>
</feed>

由 local.ch 生成(来自瑞士的电话簿(

在这篇文章(InvalidOperationException 反序列化 Atom XML(中，我创建了这个小小的控制台应用程序：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
namespace consXMLtest
{
class Program
{
static void Main(string[] args)
{
XmlSerializer xs = new XmlSerializer(typeof(RssFeedModel));
XmlTextReader reader = new XmlTextReader(@"D:/test.xml");
RssFeedModel rssFeedModel = (RssFeedModel)xs.Deserialize(reader);
Console.WriteLine(rssFeedModel.Title);
Console.ReadKey();
}
}
}
[XmlRoot("feed", Namespace = "http://www.w3.org/2005/Atom")]
public class RssFeedModel
{
[XmlElement("title")]
public string Title { get; set; }
[XmlElement("link")]
public List<Link> link { get; set; }
[XmlElement("entry")]
public List<Entry> entry { get; set; }
}
[XmlRoot("link")]
public class Link
{
[XmlAttribute("rel")]
public string rel { get; set; }
[XmlAttribute("type")]
public string type { get; set; }
}
[XmlRoot("entry")]
public class Entry
{
[XmlElement("id")]
public string Id { get; set; }
[XmlElement("published")]
public DateTime PublishDate { get; set; }
[XmlElement("content")]
public Content content { get; set; }
}
[XmlRoot("content")]
public class Content
{
[XmlAttribute("type")]
public string type { get; set; }
[XmlText]
public string text { get; set; }
}

现在我的问题：如何访问"内容"类？ 对于我的应用程序，我只需要内容。

谢谢你的帮助。

来自瑞士的问候 二州

Answer 1

如果我理解正确，您只需遍历所有条目

foreach(var c in rssFeedModel.entry)            
Console.WriteLine(c.content.text);

并且可以读出content属性。

Answer 2

试试这个：

public static void Main()
{
XmlSerializer xs = new XmlSerializer(typeof(RssFeedModel));
XmlTextReader reader = new XmlTextReader(@"D:/test.xml");
RssFeedModel rssFeedModel = (RssFeedModel)xs.Deserialize(reader);

Console.WriteLine(rssFeedModel.entry.FirstOrDefault()?.content.text);
Console.ReadKey();
}