我想通过对两个表执行join
来获得计数,我正在执行group by
和left join
。
但是,如果这个记录与另一张表不匹配,我就不会得到所有的一行。
在给定的查询中:
create table UserTable (
Id integer not null,
Name varchar(12) not null
);
insert into UserTable values (1, 'A B');
insert into UserTable values (2, 'A C');
insert into UserTable values (3, 'A C A C');
insert into UserTable values (4, 'A C C');
insert into UserTable values (5, 'A C B');
insert into UserTable values (6, 'A C C');
insert into UserTable values (7, 'A C D');
insert into UserTable values (8, 'A C E');
insert into UserTable values (9, 'A C F');
create table LogTable (
LogId integer not null,
Username varchar(12) not null,
Event varchar(12) not null
);
insert into LogTable values (1, 'A C A C', 'Read');
insert into LogTable values (2, 'A C F', 'Write');
insert into LogTable values (3, 'A C F', 'Read');
insert into LogTable values (4, 'A C C', 'Update');
insert into LogTable values (5,'A C C', 'Read');
insert into LogTable values (6,'A C F', 'Read');
insert into LogTable values (7,'A C F', 'Update');
insert into LogTable values (7,'A C F', 'Write');
insert into LogTable values (7,'A C E','Update');
insert into LogTable values (7,'A C F', 'Delete');
insert into LogTable values (10,'A C B', 'Delete');
insert into LogTable values (11, 'A C F','Copy');
insert into LogTable values (12, 'A C B','Read');
insert into LogTable values (13, 'A C F','Update');
insert into LogTable values (14, 'A C F','Copy');
insert into LogTable values (15, 'A C F','Read');
insert into LogTable values (16, 'A C F','Update');
insert into LogTable values (17, 'A C F','Copy');
insert into LogTable values (18, 'A C C','Read');
insert into LogTable values (19, 'A C D','Update');
我正在做:
SELECT COUNT(*) as Read,UT.Name, UT.Id
FROM UserTable UT
LEFT JOIN LogTable LT ON LT.Username = UT.Name
WHERE LT.Event = 'Read'
GROUP by UT.Name, UT.Id
我想要的是从UserTable
中获取所有记录,如果LogTable
中不存在
如果不存在,则将ReadCount
设为0。
为什么Left Joining没有返回此查询中UserTable的所有记录?
期望输出:
Id | Name | ReadCount
-----------------------------
1 | A B | 0
2 | A C | 0
3 | A C A C | 1
4 | A C C | 2
5 | A C B | 1
6 | A C C | 2
7 | A C D | 0
8 | A C E | 0
9 | A C F | 3
您需要将条件移动到ON
子句中。但是,您不需要COUNT(*)
,因为您要计算匹配的数量。那就是:
SELECT UT.Name, UT.Id , COUNT(LT.UserName) as num_read
FROM UserTable UT LEFT JOIN
LogTable LT
ON LT.Username = UT.Name AND LT.Event = 'Read'
GROUP by UT.Name, UT.Id;
也就是说,这种类型的查询通常比相关的子查询更快:
select ut.*,
(select count(*)
from logtable lt
where lt.username = ut.name and lt.event = 'Read'
) as num_read
from usertable ut;
特别地,这可以利用logtable(username, event)
上的索引。
SELECT COUNT(*) as Read,UT.Name, UT.Id
FROM UserTable UT
LEFT JOIN LogTable LT ON LT.Username = UT.Name
WHERE LT.Event = 'Read'
GROUP by UT.Name, UT.Id
您使用了WHERE LT.Event = 'Read'
,这使它成为内部联接,这就是为什么您没有获得左表的所有行
SELECT COUNT(*) as Read,UT.Name, UT.Id
FROM UserTable UT
LEFT JOIN LogTable LT ON LT.Username = UT.Name
and LT.Event = 'Read'
GROUP by UT.Name, UT.Id
移动条款中的条件