Django 模式引导表单的错误处理

Question

我在 Django 中创建了两个表单：一个用于注册新用户，一个用于登录用户。它们工作正常，但我想实现一个 Ajax 控件：如果出现错误，页面不会重新加载，而是模式窗口停留在那里并显示错误。

这是我的观点

def register(request):
    registered = False
    if request.method == 'POST':
        user_form = CustomUserCreationForm(request.POST)
        if user_form.is_valid():
            user = user_form.save()
            registered = True
            return render(request, 'blog/registered.html')
        else:
            print user_form.errors
    else:
        user_form = CustomUserCreationForm()
    return render(request, 'blog/post_list.html', {'user_form': user_form})
def login(request):
    if request.method == 'POST':
        login_form = CustomLoginForm(request.POST)
        email = request.POST.get('email')
        password = request.POST.get('password2')
        user = authenticate(email=email, password=password)
        if user:
            if user.is_active:
                auth_login(request, user)
                return HttpResponseRedirect('/')
            else:
                return HttpResponse("Your Pin a Voyage account is disabled.")
        else:
            print "Invalid login details: {0}, {1}".format(email, password)
            return HttpResponse("Invalid login details supplied. Get back to the <a href="/">homepage</a>.")
    else:
        login_form = CustomLoginForm()
    return render(request, 'blog/post_list.html', {'login_form': login_form})

表格

@parsleyfy
class CustomUserCreationForm(UserCreationForm):
    """
    A form that creates a user, with no privileges, from the given email and password.
    """
    email = forms.EmailField(label='', required=True, widget = forms.TextInput(
        attrs = {
            'placeholder': 'E-Mail',
            'class': 'form-control'
        }
    ))
    first_name = forms.CharField(label='', required=True, widget = forms.TextInput(
        attrs = {
            'placeholder': 'First name',
            'class': 'form-control'
        }
    ))
    second_name = forms.CharField(label='', required=True, widget = forms.TextInput(
        attrs = {
            'placeholder': 'Last name',
            'class': 'form-control'
        }
    ))
    password1 = forms.CharField(label='', required=True, widget=forms.PasswordInput(attrs = {
            'placeholder': 'Password',
            'class': 'form-control'
        }))
    password2 = forms.CharField(label='', required=True, widget=forms.PasswordInput(attrs = {
            'placeholder': 'Password confirmation (enter the same password as above, for verification)',
            'equalto': "new_password1",
            'error-message': "Your passwords do not match.",
            'class': 'form-control'
        }))
    class Meta:
        model = CustomUser
        fields = ("email", "first_name", "second_name",)
    def save(self, commit=True):
        user = super(CustomUserCreationForm, self).save(commit=False)
        user.set_password(self.cleaned_data['password2'])
        if commit:
            user.save()
        return user

@parsleyfy
class CustomLoginForm(forms.ModelForm):
    """
    A form that login a user.
    """
    email = forms.EmailField(label='', required=True, widget = forms.TextInput(
        attrs = {
            'placeholder': 'E-Mail',
            'class': 'form-control'
        }
    ))
    password2 = forms.CharField(label='', required=True, widget=forms.PasswordInput(attrs = {
            'placeholder': 'Password',
            'class': 'form-control'
        }))
    class Meta:
        model = CustomUser
        fields = ('email',)

这是模板

    <!-- Trigger the modal with a button -->
    <a id="login_btn" class="btn_sub_log top-menu"><span class="glyphicon glyphicon-lock"></span></a>
    <!-- Modal -->
    <div class="modal fade" id="login_modal" role="dialog">
        <div class="modal-dialog">
            <!-- Modal content-->
            <div class="modal-content">
                <div class="modal-header">
                    <button type="button" class="close" data-dismiss="modal">&times;</button>
                    <h3 class="modal-title" id="sign-up">Login with Pin a Voyage</h3>
                </div>
            <div class="modal-body">
                <form data-parsley-validate method="post" action="/login/" enctype="multipart/form-data">
                    {% csrf_token %}
                    {% if next %}
                        <input type="hidden" name="next" value="{{ next }}" />
                    {% endif %}
                    {{ login_form.as_p }}
                    <input type="submit" class="btn btn-info submit" name="submit" value="Login" />
                </form>
            </div>
            <div class="modal-footer">
                <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
            </div>
            </div>
        </div>
    </div>
    <!-- Trigger the modal with a button -->
    <a id="subscribe_btn" class="btn_sub_log"><h2 class="top-menu sign-up">Sign up!</h2></a>
    <!-- Modal -->
    <div class="modal fade" id="subscribe_modal" role="dialog">
        <div class="modal-dialog">
            <!-- Modal content-->
            <div class="modal-content">
                <div class="modal-header">
                    <button type="button" class="close" data-dismiss="modal">&times;</button>
                    <h3 class="modal-title" id="sign-up">Register with Pin a Voyage</h3>
                </div>
            <div class="modal-body">
                <form data-parsley-validate id="user_form" method="post" action="/register/" enctype="multipart/form-data">
                    {% csrf_token %}
                    {{ user_form.as_p }}
                    <input type="submit" class="btn btn-info submit" name="submit" value="Register" />
                </form>
            </div>
            <div class="modal-footer">
                <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
            </div>
            </div>
        </div>
    </div>

执行此操作的最佳做法是什么？

Answer 1

为此，您需要使用 JavaScript 在表单发送到服务器之前对其进行验证。 我推荐欧芹图书馆;您可以使用小部件 attrs 将正确的类和 attr 添加到表单中，然后包含 Parsley 脚本，我相信这是给定您当前代码将验证添加到前端的最简单方法。