我必须编写一个查询,我需要获取上周,上个月和所有人的记录。对于这个问题,我写了 3 个不同的查询(上周、上个月和所有查询)
每周信息:-
SELECT bu.brand_name AS 'Brand_Name',COUNT(s.unique) AS '# Item Sold',SUM(s.price) AS 'Total_Price'
FROM item_details s
LEFT JOIN sales_order o ON s.fk_sales_order = o.id_sales_order
LEFT JOIN customer_info AS c ON o.fk_customer_id = c.id_customer
LEFT JOIN simple_details cc ON s.unique = cc.unique
LEFT JOIN config_details cf ON cc.fk_config_id = cf.config_id
LEFT JOIN brand_details cb ON cf.fk_brand_id = cb.brand_id
LEFT JOIN category_details ctc ON cf.fk_category_id = ctc.category_id
LEFT JOIN gender_details g ON cf.fk_gender_id = g.gender_id
LEFT JOIN buyers AS bu ON bu.brand_name = cb.name AND bu.category_name = ctc.name AND bu.gender = g.name
WHERE bu.buyers = 'xyz' AND DATE_FORMAT(o.created_date,'%Y-%m-%d') >= @weekstartdate AND DATE_FORMAT(o.created_date,'%Y-%m-%d') <= @weekenddate
GROUP BY bu.brand_name
每月信息:-
SELECT bu.brand_name AS 'Brand_Name',COUNT(s.unique) AS '# Item Sold',SUM(s.price) AS 'Total_Price'
FROM item_details s
LEFT JOIN sales_order o ON s.fk_sales_order = o.id_sales_order
LEFT JOIN customer_info AS c ON o.fk_customer_id = c.id_customer
LEFT JOIN simple_details cc ON s.unique = cc.unique
LEFT JOIN config_details cf ON cc.fk_config_id = cf.config_id
LEFT JOIN brand_details cb ON cf.fk_brand_id = cb.brand_id
LEFT JOIN category_details ctc ON cf.fk_category_id = ctc.category_id
LEFT JOIN gender_details g ON cf.fk_gender_id = g.gender_id
LEFT JOIN buyers AS bu ON bu.brand_name = cb.name AND bu.category_name = ctc.name AND bu.gender = g.name
WHERE bu.buyers = 'xyz' AND DATE_FORMAT(o.created_date,'%Y-%m-%d') >= @monthstartdate AND DATE_FORMAT(o.created_date,'%Y-%m-%d') <= @monthenddate
GROUP BY bu.brand_name
对于所有记录:-
SELECT bu.brand_name AS 'Brand_Name',COUNT(s.unique) AS '# Item Sold',SUM(s.price) AS 'Total_Price'
FROM item_details s
LEFT JOIN sales_order o ON s.fk_sales_order = o.id_sales_order
LEFT JOIN customer_info AS c ON o.fk_customer_id = c.id_customer
LEFT JOIN simple_details cc ON s.unique = cc.unique
LEFT JOIN config_details cf ON cc.fk_config_id = cf.config_id
LEFT JOIN brand_details cb ON cf.fk_brand_id = cb.brand_id
LEFT JOIN category_details ctc ON cf.fk_category_id = ctc.category_id
LEFT JOIN gender_details g ON cf.fk_gender_id = g.gender_id
LEFT JOIN buyers AS bu ON bu.brand_name = cb.name AND bu.category_name = ctc.name AND bu.gender = g.name
WHERE bu.buyers = 'xyz'
GROUP BY bu.brand_name
这些工作正常(提供当前输出)。但问题是,我必须将这三个查询合并为一个查询。其中输出应为品牌名称, item_sold(周), total_price(周), item_sold(月), total_price(月), item_sold(全部), total_price(全部)如何编写此查询?
如果不深入研究您的代码,显而易见的解决方案是
SELECT
all.brand_name
pw.items_sold items_sold_week
pw.total_price total_price_week
pm.items_sold items_sold_month
pm.total_price total_price_month
all.items_sold items_sold_all
all.total_price total_price_all
FROM
(your all-time select) all
JOIN (your per-month select) pm ON all.brand_name = pm.brand_name
JOIN (your per-week select) pw ON all.brand_name = pw.brand_name
尽管您可能应该重新考虑整个方法,并确保是否真的希望在数据库层中使用这种逻辑,或者最好在应用程序中使用这种逻辑。
case
将聚合限制为行的子集:
select bu.brand_name
, count(case when date_format(o.created_date,'%Y-%m-%d') >= @weekstartdate
and date_format(o.created_date,'%Y-%m-%d') <= @weekenddate
then 1 end) as '# Item Sold Week'
, sum(case when date_format(o.created_date,'%Y-%m-%d') >= @weekstartdate
and date_format(o.created_date,'%Y-%m-%d') <= @weekenddate
then s.price end) as 'Total_Price Week'
, count(case when date_format(o.created_date,'%Y-%m-%d') >= @monthstartdate
and date_format(o.created_date,'%Y-%m-%d') <= @monthstartdate
then 1 end) as '# Item Sold Month'
, ...
如果所有三个选择都使用结果中的相同字段,则可以将它们联合起来:
SELECT *
FROM (SELECT 1) AS a
UNION (SELECT 2) AS b
UNION (SELECT 3) AS c
如果您需要告诉彼此的周/月/所有记录 - 只需添加包含"周"或"周一"的常量字段
您可以在查询之间使用 UNION.关键字将它们捆绑在一起。但是列类型和顺序在所有查询中必须相同。您可以为每个集合添加一个标识符