如何使用Services_JSON软件包在PHP中解码JSON(PHP可捕致命错误:类STDClass的对象无法将其转换

Question

我想使用JSON编码/解码数组。由于我拥有Php 5.1.6，因此我使用的是Pear's（http://pear.php.net/pepr/pepr-proposal-show.php?id=198）。使用它，我可以编码，但是，我无法解码我尝试阅读文档，但什么都不了解。我的代码是：

<?php  include("/home/gpreeti/php/JSON.php");
$json = new Services_JSON();
$marks = array(
            "mohammad" => array (
               "physics" => 35,
               "maths" => 30,
               "chemistry" => 39
            ),
            "qadir" => array (
               "physics" => 30,
               "maths" => 32,
               "chemistry" => 29
            ),
            "zara" => array (
               "physics" => 31,
               "maths" => 22,
               "chemistry" => 39
            )
         );
$marks=$json->encode($marks);
print"$marksn";
$marks = $json->decode($marks);
#var_dump($marks);
print"$marks";
?>

在运行它时，我得到了这个

{"mohammad":{"physics":35,"maths":30,"chemistry":39},"qadir":{"physics":30,"maths":32,"chemistry":29},"zara":{"physics":31,"maths":22,"chemistry":39}}
PHP Catchable fatal error:  Object of class stdClass could not be converted to string in /servers/scratch05/gpreeti/php_pgms/test_json.php on line 26

请帮忙，谢谢

Answer 1

当您具有数组/对象时，您需要使用print_r / var_dump显示它。打印用于字符串

$marks=$json->encode($marks);
print"$marksn";
$marks = $json->decode($marks);
#var_dump($marks);
print_r($marks); //change this line

edit 要获得以下更改需要进行的数组：

$json = new Services_JSON(SERVICES_JSON_LOOSE_TYPE);
$marks = $json->decode($marks);