如何将两个日期之间的每个日期生成到给定的粒度?
我想使这个扩展垫成为日期数组,它们都必须在 00m、15m、30m 或 45m 处,这样就不会有间隙。(可选)设置不在原始集中的开始日期和结束日期(以便您可以有前导日期和尾随日期)。
extension TimeSeries {
var earliest: Date? {
return timeSeries.map { $0.date }.min()
}
var latest: Date? {
return timeSeries.map { $0.date }.max()
}
func pad (to repletion: Int, _ component: Calendar.Component, from: Date? = nil, to: Date? = nil) {
guard let start = from ?? self.earliest else {
print("no start date given and none available")
return
}
guard let end = to ?? self.latest else {
print("no end date given and none available")
return
}
// magic happens here...
}
}
具体来说,给定:
[ Date/* 2018-01-16 01:15:00 */, Date/* 2018-01-16 01:45:00 */]
我希望数组变成:
[ Date/* 2018-01-16 01:15:00 */, Date/* 2018-01-16 01:30:00 */, Date/* 2018-01-16 01:45:00 */]
如果它被称为ts.pad(to: 15, .minutes, from: Date/* 2018-01-16 01:00:00 */, to: Date/* 2018-01-16 02:00:00 */ )
我希望数组变成:
[ Date/* 2018-01-16 01:00:00 */, Date/* 2018-01-16 01:15:00 */, Date/* 2018-01-16 01:30:00 */, Date/* 2018-01-16 01:45:00 */, Date/* 2018-01-16 02:00:00 */]
逻辑可能是这样的。创建以开始日期作为第一个元素的数组。然后将添加组件的日期附加到最后一个日期,直到新日期应大于结束日期
func pad(to repletion: Int, _ component: Calendar.Component, from: Date? = nil, to: Date? = nil) {
guard let start = from ?? self.earliest, let end = to ?? self.latest else {
print("no date given and none available")
return
}
var components = DateComponents()
components.setValue(repletion, for: component)
let calendar = Calendar.current
var dates = [start] // results
while start < end {
if let newDate = calendar.date(byAdding: components, to: dates.last!),
newDate <= end {
dates.append(newDate)
} else { break }
}
}
这是我
的变体,假设周期由start
和end
日期给出
let quarter: TimeInterval = 15 * 60
let dateInterval = DateInterval(start: start, end: end)
var date = start
var result = [Date]()
while dateInterval.contains(date) {
result.append(date)
date = date.addingTimeInterval(quarter)
}