我正在尝试制作一个简单的文本加密器(并非所有功能都完整),但我有一个特定的问题,我希望得到一些帮助。在这一点上,我停止了编码,并添加了一些注释文档进行测试:
在函数algorithm()中:第16-25行将std::string ck[]的索引附加到嵌套循环内的std::string KEY。外部循环正在运行PASSWORD.size()的度量值,并针对所有ck[]检查每个PASSWORD.substr(…)。
然而,输出结果只是PASSWORD的第一个和最后一个字符的索引值。例如,如果PASSWORD=abc KEY输出0002。我希望整个密码变成KEY(按规定)。
#include <string.h>
#include <iostream>
#include <stdlib.h>
#include <sstream>
std::string PASSWORD, KEY, ENCRYPTED_TEXT;
void algorithm(std::string note){
ENCRYPTED_TEXT.append(note);
/**STANDARD RULESET**/
std::string ck[] = { "a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9" };
for(int x=0;x<PASSWORD.size();x++){
for(int y=0;y<sizeof(ck)/4;y++){
if(PASSWORD.substr(x,x+1)==ck[y]){
std::stringstream ind;
if(y>9) ind << y+1;
else ind << "0" << y;
KEY.append(ind.str());
}
}
}
std::cout << "nKey is " << KEY;
//make_file(ENCRYPTED_TEXT);
}
void qn_setup(){
bool ask=true;
while(ask=true){
std::string check1="", check2="";
std::cout << "Type a password:n";
std::cin >> check1;
std::cout << "Confirm password:n";
std::cin >> check2;
if(check1==check2) {
PASSWORD=check1;
ENCRYPTED_TEXT=check1;
ask=false;
break; }
else { std::cout << "nPasswords did not match.n"; }
}
}
int main(){
qn_setup();
algorithm(""); //testing key
}
没有任何语法错误,只有逻辑错误。
字符串子字符串(size_t pos=0,size_t n=npos)常量;
Generate substring Returns a string object with its contents initialized to a substring of the current object. This substring is the character sequence that starts at character position pos and has a length of n characters.
所以你的支票必须是:
PASSWORD.substr(x,1)==ck[y] /* instead of PASSWORD.substr(x,x+1) */